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3 years ago

In the diagram, point O is the center of the circle and m∠ADB = 43°. If m∠AOB = m∠BOC, what is m∠BDC?

Mathematics

2 answers:

VMariaS [17]3 years ago

6 0

Bruh idk this is hard.

lana [24]3 years ago

5 0

Answer:

Step-by-step explanation:

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Which proportion could you use to convert 4.5 tons to pounds?<br><br><br><br> 4.5 tons =____ pounds

mina [271]

Answer:

9000 pounds

Step-by-step explanation:

Since there are 2,000 pounds in a ton, you should use the proportion on the left.

Solve the equation:

$\frac{2000}{1} = \frac{?}{4.5} \\(2000)(4.5) = 9000$

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2 years ago

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Molly is buying apple juice for a class party. There will be 26 people coming and each person drank 1.89 cups. How many fluid ou

dimaraw [331]

I believe she will need 49.14 ounces

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3 years ago

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Eleanor can drive an average of 374 miles on one tank of gas. How many miles can she drive on 15 tanks of gas?

lidiya [134]

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3 years ago

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What is the simplified form of the following expression?

USPshnik [31]

Option C:

$$\frac{\sqrt[3]{100 x}}{5}=\sqrt[3]{\frac{4 x}{5}}$

Solution:

Given expression is

$$\sqrt[3]{\frac{4 x}{5}}$

Note: $\sqrt[3]{125}=\sqrt[3]{{5^3}} = 5$

To find the correct expression for the above simplified expression.

Option A: $\frac{\sqrt[3]{4 x}}{5}$

5 can be written as $\sqrt[3]{125}$ .

$$\frac{\sqrt[3]{4 x}}{5}=\frac{\sqrt[3]{4 x}}{\sqrt[3]{125} }$

$$=\sqrt[3]{\frac{4x}{125} }$

It is not the given simplified expression.

Option B: $\frac{\sqrt[3]{20 x}}{5}$

$$\frac{\sqrt[3]{20 x}}{5}=\frac{\sqrt[3]{20 x}}{\sqrt[3]{125} }$

$$=\sqrt[3]{\frac{20x}{125} }$

Cancel the common factor in both numerator and denominator.

$$=\sqrt[3]{\frac{4x}{25} }$

It is not the given simplified expression.

Option C: $\frac{\sqrt[3]{100 x}}{5}$

$$\frac{\sqrt[3]{100 x}}{5}=\frac{\sqrt[3]{100 x}}{\sqrt[3]{125} }$

$$=\sqrt[3]{\frac{100x}{125} }$

Cancel the common factor in both numerator and denominator.

$$=\sqrt[3]{\frac{4 x}{5}}$

It is the given simplified expression.

Option D: $\frac{\sqrt[3]{100 x}}{125}$

$$\frac{\sqrt[3]{100 x}}{125}=\frac{\sqrt[3]{100 x}}{5^3}$

It is not the given simplified expression.

Hence Option C is the correct answer.

$$\frac{\sqrt[3]{100 x}}{5}=\sqrt[3]{\frac{4 x}{5}}$

3 0

3 years ago

Given two points m and n on the coordinate plane, find the slope of line mn, and state the slope of the line perpendicular to li

ololo11 [35]

The slope of the line MN where M (9,6) and N (1,4) can be obtained by obtaining the rate of the rise over the run. This is shown below:

(y2 - y1)/(x2 - x1) = (4 - 6)/(1 - 9) = (-2)/(-8)
m1 = 1/4

The slope of the line perpendicular to line MN can be obtained by taking the negative reciprocal of the slope of line MN.

m1 = 1/4
m2 = -1/m1 = -1/(1/4) = -4

Therefore, the slope of the line perpendicular to line MN is -4.

3 0

3 years ago