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2 years ago

Can anyone help? It’s not 14, I’ll give Brainly + 15 pts

Mathematics

1 answer:

Julli [10]2 years ago

8 0

Short side length = x

Medium side = x + 7

Long side = 5x

Total 49, so

x + x + 7 + 5x = 49

If you combine like terms:

7x + 7 = 49

Subtract 7 from both sides

7x = 42

Divide both sides by 7

x = 6 inches.

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A city has a population of 310,000 people. Suppose that each year the population grows by 9%. What will the population be after

Leno4ka [110]

Answer: 644,800

Step-by-step explanation:

This can also be solved using the terms of Arithmetic Progressions.

Let the 13 years be number of terms of the sequences (n)

Therefore ;

T₁₃ = a + ( n - 1 )d , where a = 310,000 and d = 9% of 310,000

9% of 310,000 = 9/100 x 310,000

= 27,900

so the common difference (d)

d = 27,900

Now substitute for the values in the formula above and calculate

T₁₃ = 310,000 + ( 13 - 1 ) x 27,900

= 310,000 + 12 x 27,900

= 310,000 + 334,800

= 644,800.

The population after 13 years = 644,800.

3 0

2 years ago

Write a recursive rule for the sequence.<br> –2, 4, –8, 16, . . .

VMariaS [17]

$a_{n} = (-2)^{n}$

4 0

2 years ago

Please help me thank you

ladessa [460]

Answer:

Step-by-step explanation:

5 0

3 years ago

Each unit costs 14p how much does942 cost???????????????????????????????????????????????????????????????????????????????????????

Fynjy0 [20]

Answer:

13188

Step-by-step explanation:

7 0

3 years ago

Given that α and β are the roots of the quadratic equation <img src="https://tex.z-dn.net/?f=2x%5E%7B2%7D%20%2B6x-7%3Dp" id="Tex

siniylev [52]

Answer:

$\large \boxed{\sf \ \ \ p=-11 \ \ \ }$

Step-by-step explanation:

Hello,

$\alpha \text{ and } \beta \text{ are the roots of the following equation}$

$2x^2+6x-7=p$

It means that

$2\alpha^2+6\alpha-7=p \\\\2\beta ^2+6\beta -7=p \\\\$

And we know that

$\alpha= 2\cdot \beta$

So we got two equations

$2(2\beta)^2+6\cdot 2 \cdot \beta -7=p \\\\8\beta^2+12\beta -7=p\\\\ and \ 2\beta ^2+6\beta -7=p \ So \\\\\\8\beta^2+12\beta -7 = 2\beta ^2+6\beta -7\\\\6\beta^2+6\beta =0\\\\\beta(\beta+1)=0\\\\ \beta =0 \ or \ \beta=-1$

For $\beta =0, \ \ \alpha =0, \ \ p = -7$

For $\beta =-1, \ \ \alpha =-2, \ \ p= 2-6-7=-11, \ p=2*4-12-7=-11$

I assume that we are after two different roots so the solution for p is p=-11

b) $\alpha +2 =-2+2=0 \ and \ \beta+2=-1+2=1$

So a quadratic equation with the expected roots is

$x(x-1)=x^2-x$

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

3 0

2 years ago