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3 years ago

In the number 23.45, the digit 2 is in the Select... place.

Mathematics

2 answers:

borishaifa [10]3 years ago

6 0

Answer:

tens place

Step-by-step explanation:

tens ones . tenths hundredths

2 3 . 4 5

jekas [21]3 years ago

4 0

Number 2 is in the tens place.

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Thereisalinethatincludesthepoint(1, -10)andhasaslopeof

Paladinen [302]

Answer:

i dont know i am so sorry

Step-by-step explanation:

good luck with it though

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3 years ago

Mariah spent $9.50 on 9 pounds of limes and pears. Limes cost $0.50 per pound and pears cost $1.50 per pound. Let l be the numbe

Mashcka [7]

Answer:

4 pounds of lime and 5 pounds of pears

Step-by-step explanation:

I + P = 9

0.5l + 1.5P = 9.5

I = 9 - P

0.5(9 - P) + 1.5P = 9.5

4.5-0.5P + 1.5P = 9.5

4.5 + P (1P) = 9.5

P = 9.5-4.5 = 5

I = 9 - 5 = 4

Answer: 4 pounds of lime and 5 pounds of pears

5 0

3 years ago

Does the point(1, 8)satisfy the inequality y ≥ 6x + 2 ?

nalin [4]

Answer: Yes

Step-by-step explanation:

1. Substitute 1 for x

2. 6 times 1 is 6 plus 2 is 8

3.8 is equal to or greater than 8

4 0

3 years ago

Can anyone help it would mean alot im struggling right now

Setler79 [48]

Answer:

what do you need? ^-^ I can help you

6 0

3 years ago

Which set of numbers could represent the lengths of the sides of a right triangle?

DiKsa [7]

Answer:

The first set: 8, 15, and 17.

Step-by-step explanation:

By the pythagorean theorem, a triangle is a right triangle if and only if

$\text{longest side}^2 = \text{first shorter side}^2 + \text{second shorter side}^2$ .

In this case,

$\text{longest side}^2 = 17^2 = 289$ .

$\begin{aligned}&\text{first shortest side}^2 + \text{second shortest side}^2 \\ &= 8^2 + 15^2\\ &=64 + 225 = 289 \end{aligned}$ .

In other words, indeed $\text{hypotenuse}^2 = \text{first leg}^2 + \text{second leg}^2$ . Hence, 8, 15, 17 does form a right triangle.

Similarly, check the other pairs. Keep in mind that the square of the longest side should be equal to the sum of the square of the two

Factor out the common factor $2$ to simplify the calculations.

$\text{longest side}^2 = 20^2 = 400$

$\begin{aligned}&\text{first shortest side}^2 + \text{second shortest side}^2 \\ &= 10^2 + 15^2\\ &=100 + 225 = 325 \end{aligned}$ .

$\text{longest side}^2 \ne \text{first shorter side}^2 + \text{second shorter side}^2$ .

Hence, by the pythagorean theorem, these three sides don't form a right triangle.

$\text{longest side}^2 = (2\times 11)^2 = 2^2 \times 121$ .

$\begin{aligned}&\text{first shortest side}^2 + \text{second shortest side}^2 \\ &= (2 \times 6)^2 + (2 \times 9)^2\\ &=2^2 \times(36 + 81) = 2^2 \times 117 \end{aligned}$ .

$\text{longest side}^2 \ne \text{first shorter side}^2 + \text{second shorter side}^2$ .

Hence, by the pythagorean theorem, these three sides don't form a right triangle.

$\text{longest side}^2 = 11^2 = 121$ .

<h3> $\begin{aligned}&\text{first shortest side}^2 + \text{second shortest side}^2 \\ &= 7^2 + 9^2\\ &=49+ 81 = 130 \end{aligned}$ .</h3>

$\text{longest side}^2 \ne \text{first shorter side}^2 + \text{second shorter side}^2$ .

Hence, by the pythagorean theorem, these three sides don't form a right triangle.

6 0

4 years ago