Given that a polynomial function P(x) has rational coefficients.
Two roots are already given which are i and 7+8i,
Now we have to find two additional roots of P(x)=0
Given roots i and 7+8i are complex roots and we know that complex roots always occur in conjugate pairs so that means conjugate of given roots will also be the roots.
conjugate of a+bi is given by a-bi
So using that logic, conjugate of i is i
also conjugate of 7+8i is 7-8i
Hence final answer for the remaining roots are (-i) and (7-8i).
<u>Step-by-step explanation:</u>
(a) A natural number that is greater than 25 and less than 40
Natural Number : These are numbers starting from 1 or also sometimes from zero and are all positive ! A natural greater than 25 & less than 40 is 30 .
(b) An integer which is less than -5 and a multiple of 2
Integer : An integer is a whole number not a fraction including 0 . It can be positive or negative ! Integer less than -5 and a multiple of 2 is -6.
(c) A rational number between 1 and 2
Rational Number : A number which can be expressed in form of p/q where q is not equal to 0 . A rational number between 1 & 2 is 3/2 .
(d) An irrational number between 8 and 9.
Irrational Number: A real number which is not rational or can't be written in form of p/q . An irrational number between 8 & 9 is
.
Answer:
14x
Step-by-step explanation:
multiply the 2i by the 0 eulogistic quotient
These | | simple mean absolute value. Absolute value is simply the number positive, for example, the absolute value of -3 is simply 3
Answer:
cross out 4
Step-by-step explanation:
explanation