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2 years ago

The variable cost for a product is $1, and the total fixed cost are $300,222. The company sells

Mathematics

1 answer:

Lady_Fox [76]2 years ago

4 0

Answer:

42,889

Step-by-step explanation:

The contribution margin of a product is $8 -1 = $7. Then the number that must be sold to cover fixed costs is ...

$300,222/$7 = 42,888.9

To break even, the company must sell 42,889 products.

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A sequence which terminates is called

vivado [14]

If a sequence terminates it is called a finite sequence

5 0

3 years ago

On a shelf containing 53 comic books, 21 are Marvel titles, 17 are DC titles, 12 are Dark Horse titles, and 3 are Harvey titles.

Marizza181 [45]

Answer:

68% or $\frac{36}{53}$

Step-by-step explanation:

In order to find the probability of Geraldo selecting a comic that isn't a DC title, we have to subtract the amount of comics that are DC titles from the total amount of comics and then divide that number by the total amount of comics.

53 - 17 = 36

36/53 = 0.679

Geraldo has a 68% chance of choosing a comic that isn't a DC title.

8 0

3 years ago

F(t)=8.50(1.15)^3 (the 3 means to the third powers). This in my test I'm taking right now, please yall I need someone one to sol

Vinil7 [7]

Answer:

12.9

Step-by-step explanation:

Given data

Give the expression

F(t)=8.50(1.15)^3

Let us solve the term in the bracket

F(t)=8.50*1.520875

F(t)=12.9

Hence the final answer is 12.9

4 0

2 years ago

A travelling salesman sells milkshake mixing machines and on average sells 8.9 machines per month. He needs to sell at least 3 m

Goshia [24]

Answer:

0.67% probability he will have to shut down after this month

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given time interval.

On average sells 8.9 machines per month.

So $\mu = 8.9$

Using the Poisson distribution, what is the probability he will have to shut down after this month

If he sells less than 3 machines.

$P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2)$

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-8.9}*8.9^{0}}{(0)!} = 0.0001$

$P(X = 1) = \frac{e^{-8.9}*8.9^{1}}{(1)!} = 0.0012$

$P(X = 2) = \frac{e^{-8.9}*8.9^{2}}{(2)!} = 0.0054$

$P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2) = 0.0001 + 0.0012 + 0.0054 = 0.0067$

0.67% probability he will have to shut down after this month

5 0

2 years ago

If the fourth of 5 consecutive numebrs is 15, what is their sum?

Tju [1.3M]

BRAINLIEST PLEASEEEEEEEEEEEEE

Answer:

Step-by-step explanation:

You know the fourth number in this pattern is 15, and that they are all consecutive. With this information you know that the fifth number will be 16, and by counting backwards from 15 you can figure out all of the numbers are 12, 13, 14, 15, and 16. Now, to find the sum of these numbers you must add them together.

This is what it could look like: 12+13+14+15+16

Now to find the answer you need to calculate what the addition would equal, which is 70.

8 0

2 years ago