Question

The equation h(t)=−16t2+120t+65 gives the height of a firework, in feet, t seconds after it is launched from a platform.

Answer 1

Answer:

The height of the platform is 65 ft

Step-by-step explanation:

Let

t -----> the time in seconds after the launch of the fireworks from a platform

h(t) ----> the height of a firework in feet

we have

$h(t)=-16t^{2}+120t+65$

we know that

The height of the platform is when the value of t is equal to zero (y-intercept)

For t=0

$h(0)=-16(0)^{2}+120(0)t+65$

$h(0)=65\ ft$

therefore

The height of the platform is 65 ft

Answer 2

Answer:

65 ft

Step-by-step explanation:

We are given that an equation which gives the height of firework

$h(t)=-16t^2+120t+65$

Where h(t)=Height in feet

t=Time in seconds

Substitute t= 0

$h(0)=65 ft$

When t= 0 then height of platform =h(0)

Hence, the height of platform=65 ft

Answer: 65 ft