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A rectangle with a length of 28 and perimeter of 64 what is the width and what is the area
1 answer:
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Answer:
Length = 8 inch , Width = , This equation models the situation
Step-by-step explanation:
Given as ;
The Area of Rectangle is 12 inches²
The Length of Rectangle is 5 inches longer than twice the width
Let The Length = L inches
The Width = W inches
According to question ,
L = 5 + (2 × w )
∵ The Area of Rectangle = Length × width
Or, 12 inches² = [ 5 + (2 × w ) ] × w
Or, 12 inches² = 5 w +2 w²
Or, 2 w² + 5 w - 12 = 0
Or, 2 w² + 8 w -3 w - 12 = 0
Or, 2 w (w +4) - 3 (w + 4) = 0
I.e (w + 4) ( 2 w - 3) = 0
So , w = -4 , and w =
∴ Length = 5 + (2 × w ) =
Length = 5 + (2 × )
so , L = 5 + 3 = 8
Hence Length = 8 inch , Width = This equation models the situation Answer