Question

A rectangular building has a perimeter of 208 meters. It’s area is 2415 square meters. What are the dimensions of the building?

Answer 1

Answer:

Step-by-step explanation:

Perimeter of rectangle = 208 m

2*(l + w) = 208  {divide both sides by 2}

l +w = 208/2

l +w = 104

l = 104 - w

Area of rectangle = 2415 square meters

l*w = 2415

Substitute l = 104 - w in the above equation,

(104 - w ) *w = 2415

104w - w² = 2415

0 = 2415 - 104w + w²

w² - 104w + 2415 = 0

Sum = -104

Product  = 2415

Factors = (-69) , (-35)

w² - 35w - 69w + (-69)*(-35) = 0

w(w - 35) - 69(w - 35) = 0

(w -35)(w -69)

w - 35 = 0    ; w  -69 = 0

w = 35    ; w = 69

The dimensions of the building: 35 , 69