The answer is C. Square root of 29
These two triangles are congruent so we just have to figure out the length of two sides then use the Pythagorean theorem to solve for the last side
Pythagorean theorem:
a^2 + b^2 = c^2
We know one of the legs is 5 so:
5^2 + b^2 = c^2
25 + b^2 = c^2
The base of the triangle is 4 but since the line in the middle is a perpendicular bisector to the base, both sides of the line are equal to 2
So now we know the value of the other leg:
25 + 2^2 = c^2
25 + 4 = c^2
29 = c^2
Now you take the square root of both sides
Square root of 29 = c
~~hope this helps~~
Answer:
136 degrees
Step-by-step explanation:
From the above question, we are told that:
The measure of a tangent chord angle = 68 degrees
From circle theorems, we know that:
The measure of an angle formed by a tangent and chord(Tangent-chord angles ) is equal to half the measure of the intercepted arc.
Hence,
68° = 1/2 (measure of the intercepted arc.)
Let the Measure of the intercepted arc = x
68° = 1/2x
Divide both sides by 1/2
Measure of the Intercepted arc(x) = 68° ÷ 1/2
Measure of the Intercepted arc = 68° × 2
Measure of the Intercepted are = 136°
Therefore, the measure of the intercepted arc inside the angle is 136°
Answer:
5/51 or 9.8
Step-by-step explanation:
Since she does not put the marble back it's dependent.
1/3 chances the first marble is red and 5/17 the second is too.
Multiply and you get 5/51 odds, or approximately 9.8% chance
1. Check the picture attached.
let P, M, N be the points :P(5, -2), M(5, 0), N(0, -2)
ABP is the angle with measure ∅, where BA is the initial ray and BP the terminal ray.
2. m(PNM)=∅ as can be easily checked
In triangle PNM, NP=5, PM=2 and NM=
![\sqrt{ 5^{2} + 2^{2} }= \sqrt{25+4}= \sqrt{29}](https://tex.z-dn.net/?f=%20%5Csqrt%7B%205%5E%7B2%7D%20%2B%202%5E%7B2%7D%20%7D%3D%20%5Csqrt%7B25%2B4%7D%3D%20%5Csqrt%7B29%7D%20%20%20)
units
3. let opp=opposite side, adj=adjecent side, hyp=hypothenuse
sin ∅ = opp/hyp=
![\frac{2}{\sqrt{29}}](https://tex.z-dn.net/?f=%20%5Cfrac%7B2%7D%7B%5Csqrt%7B29%7D%7D%20)
cos ∅ = adj/hyp=
![\frac{5}{\sqrt{29}}](https://tex.z-dn.net/?f=%20%5Cfrac%7B5%7D%7B%5Csqrt%7B29%7D%7D%20)
tan ∅ = opp/adj=2/5
cot ∅ = adj/opp=5/2
sec ∅ = hyp/adj=
![\frac{\sqrt{29}}{5}](https://tex.z-dn.net/?f=%20%5Cfrac%7B%5Csqrt%7B29%7D%7D%7B5%7D%20)
csc ∅ = hyp/opp=