Answer:
when the old wooden stiff poles were being used, none of the kinetic energy during the run-up was stored in the pole. With the new fiber glass flexible pole, some of that energy is stored in the flexing of the pole and then released as the pole straightens out at the top of its arc. Where 13 ft was considered an excellent competition vault with the stiff pole, the additional boost from the stored energy in the flex pole has made 17 ft vaults the winning heights.
Explanation:
when the old wooden stiff poles were being used, none of the kinetic energy during the run-up was stored in the pole. With the new fiber glass flexible pole, some of that energy is stored in the flexing of the pole and then released as the pole straightens out at the top of its arc. Where 13 ft was considered an excellent competition vault with the stiff pole, the additional boost from the stored energy in the flex pole has made 17 ft vaults the winning heights.
The flexible fiberglass poles can bend more than wooden ones, before breaking. This meant that fiberglass poles are able to store more energy than wooden ones, and provide an additional increase in height to the vaulter, when the pole straightens out near the top of the vault.
Answer:
2 m/s²
Explanation:
the equations of motion are
S= ut +½at²
v² = u²+ 2as
v = u + at
s = (u+v)/2 × t
From the parameters given
u = 0m/s this is because it starts from rest
Distance (s) = 9m
Time (t) = 3s
Based on this the first equation would be used
s = ut + ½at²
Input values
9 = 0×3 + ½ × a x 3²
9 = 0 + 9a/2
9 = 4.5a
Divide both sides by 4.5
a = 9 / 4.5 m/s²
a = 2 m/s²
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It goes from positive to negative
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Good experimental design includes a hypothesis that is <span>testable and observable.</span>
Answer:
F= 9492.12 N
Explanation:
Given that
mass, m = 1598 kg
Initial velocity ,u= 0 km/h
Final velocity v= 93.9 km/h
v =26.08 m/s
Distance ,d= 57.2 m
We know that
v² = u² + 2 a d
a=acceleration
u=initial velocity
v= final velocity
d=distance
26.08²= 0² + 2 x a x 57.2
a= 5.94 m/s²
We know that
Force = mass x acceleration
F= m a
F= 5.94 x 1598 N
F= 9492.12 N