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muminat
3 years ago
11

A mirror forms an erect image 40cm from the object and one third its height where must the mirror be situated ​

Physics
1 answer:
Softa [21]3 years ago
7 0
  • image distance=-40cm=v
  • Object distance=u=?
  • Magnification=m=3

We know

\boxed{\sf m=-\dfrac{v}{u}}

\\ \sf\longmapsto 3=-\dfrac{-40}{u}

\\ \sf\longmapsto 3=\dfrac{40}{u}

\\ \sf\longmapsto u=\dfrac{40}{3}

\\ \sf\longmapsto u=13.3cm

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