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3 years ago

1. You are about to make a left turn. You must signal continuously during the last

Physics

1 answer:

Bingel [31]3 years ago

5 0

Answer:

Explanation:

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Judge a source's reliability

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3 years ago

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3 years ago

A pair of in-phase stereo speakers is placed side by side, 0.764 m apart. You stand directly in front of one of the speakers, 2.

Goryan [66]

Answer:

f = 2858.33 Hz

Explanation:

given,

distance between speaker (A) and the person = 2.34 m

Distance between speaker (B) and the person is AB =

= $\sqrt{(0.764)^2 + (2.34)^2}$

= 2.46 m

path difference d = BP - AP

= 2.46 - 2.34 m

= 0.12 m

now, λ = 0.12

speed of sound = 343 m/s

$f= \dfrac{c}{\lambda}$

$f= \dfrac{343}{0.12}$

f = 2858.33 Hz

the lowest frequency that will produce constructive interference is equal to

f = 2858.33 Hz

7 0

3 years ago

Drag the item from the item bank to its corresponding match.1.A fireman turns on his hose and is knocked backwards.2.It takes le

creativ13 [48]

Answer:

1 - third law

2 - second law

3 - first law

4 - third law

5 - second law

6 - first law

Explanation:

First law

In an inertial frame of reference, an object either remains at rest or continues to move at a constant velocity, unless acted upon by a force.

Second law

In an inertial frame of reference, the vector sum of the forces F on an object is equal to the mass m of that object multiplied by the acceleration, a of the object

F = ma.

Third law

When one body exerts a force on a second body, the second body simultaneously exerts a force equal in magnitude and opposite in direction on the first body.

7 0

3 years ago

If you place 48 cm object 15 m in front of a convex mirror of focal length 5 m, what is the magnification of the image?

Arisa [49]

Answer:

m = 0.25

Explanation:

Given that,

Object distance, u = -15cm

Height of the object, h = 48

Focal length, f = cm

We need to find the magnification of the image.

Let v is the image distance. Using mirror's equation.

$\dfrac{1}{v}+\dfrac{1}{u}=\dfrac{1}{f}\\\\\dfrac{1}{v}=\dfrac{1}{f}-\dfrac{1}{u}\\\\=\dfrac{1}{5}-\dfrac{1}{(-15)}\\\\=3.75\ cm$

Magnification,

$m=\dfrac{-v}{u}\\\\=\dfrac{-3.75}{-15}\\\\=0.25$

Hence, the magnification of the image is 0.25.

7 0

3 years ago