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Leto [7]
3 years ago
6

We roll 3 dice and add the results. what is the probability that the total is NOT 18?

Mathematics
1 answer:
exis [7]3 years ago
5 0
To answer this you need to find the probability that it is 18 first. The only way to get 18 is by rolling 3 6's. The probability of each 6 is 1/6. 1/6 * 1/6 * 1/6= 0.0046. That is the probability of rolling 3 die and getting 18. To get the actual answer, you just subtract that from 1
1-0.0046 equals 0.9954
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Write an equation for the vertical translation.
Lubov Fominskaja [6]

Answer:

y=-2/9 x – 9

Step-by-step explanation:

It really is simple translation because this is written in y=mx+b, where b is the given y-intercept. From there, just subtract what is needed to go down or add what is need to go up.

y=-2/9 x – 7 – 2

.:y=-2/9 x – 9

7 0
2 years ago
1. Consider the data set 1,2,3,4,5,6,7,8,9.
ivanzaharov [21]

Answer:  a) Mean = 5, Median = 5

b) Mean = 15, Median = 5

c) Due to presence of outlier i.e. 99.

Step-by-step explanation:

Since we have given that

1,2,3,4,5,6,7,8,9

Here, n = 9 which is odd

So, Mean would be

\dfrac{1+2+3+4+5+6+7+8+9}{9}=\dfrac{45}{9}=5

Median = (\dfrac{n+1}{2})^{th}=\dfrac{9+1}{2}=5^{th}=5

If 9 is replaced by 99,

1,2,3,4,5,6,7,8,99

So, mean would be

\dfrac{1+2+3+4+5+6+7+8+99}{9}=\dfrac{135}{9}=15

Median would be same as before i.e. 5

The mean is neither central nor typical for the data due to outlier i.e. 99

Hence, a) Mean = 5, Median = 5

b) Mean = 15, Median = 5

c) Due to presence of outlier i.e. 99.

5 0
3 years ago
I have $1000 invested in a coin worth $43000. If the coin reaches $100000 how much will I have invested?
Pavel [41]

Answer:

$2326

Step-by-step explanation:

I have $1000 invested in a coin worth $43000. If the coin reaches $100000 how much will I have invested?

To solve the above question, we have:

$43,000 = $1000

$100,000 = x

Cross Multiply

43000 × x = 100,000 × 1000

x = 100000 × 1000/43000

x = $2325.5813953

Approximately = $2326

Therefore, If the coin reaches $100000 you would have invested $2326

8 0
3 years ago
There are 6 swimmers in a race. In how many ways can they finish in first and second place?
hodyreva [135]

Answer:

step 1. 6x2=12 first place way

step 2. 12×2=24

step 3. 24+6=30 second place way

6 0
2 years ago
Find the values of a and b.<br> a<br> The diagram is not drawn to scale.<br> a =<br> U<br> b =<br> U
nata0808 [166]

Answer:

a = 36°

b = 144°

Step-by-step explanation:

<h3><u>Method 1</u></h3>

Number of sides = n = 10

Sum of interior angles = (n - 2) × 180°

                                     = (10 - 2) × 180°

                                     = 8 × 180°

                                     = 1440°

Interior angle = b = sum of interior angles ÷ number of sides

                          b = 1440 ÷ 10

                          b = 144°

              a + b = 180° (Sum of angles in the straight line)

         a + 144° = 180°

a + 144° - 144° = 180° - 144°

                    a = 36°

<h3><u>Method 2</u></h3>

Number of sides = 10

Exterior angle = a = 360° ÷ Number of sides

                           a = 360° ÷ 10

                           a = 36°

            a + b = 180° (Sum of angles in the straight line)

        36° + b = 180°

36° + b - 36° = 180° - 36°

                 b = 144°

7 0
2 years ago
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