Surface area of cylinder is 2 (pi)rh+2(pi)r^2
this is the area of the side [(2 (pi)rh] and the two circles together [2 (pi)r^2]
122. r=24
h=15
2 (3.14)24×15+2 (3.14)24^2
6.28×24×15+6.28×24^2
2260.8+3617.28
5878.08mm
123. r=5
h=8
2 (3.14)5×8+2 (3.14)5^2
6.28×5×8+6.28×5^2
251.2+157
408.2cm
124. the surface area of a cylinder that has a hole is going to be
surface area of big cylinder-2small area circles (the holes) + the area of the holes sides
hopefully that isn't too confusing
big radius: 8
height: 14
little radius: 2.5
height: 14
2 (3.14)8×14+2 (3.14)8^2
6.28×8×14+6.28×8^2
703.36+401.92
1105.28in (area of big cylinder)
2 (3.14)2.5^2 (two small holes)
6.28×2.5^2
39.25in (area of holes)
2 (3.14)×2.5×14 (area of side)
6.28×2.5×14
219.8in
1105.28-39.25+219.8
1066.03+219.8
1285.83in total surface area
125. h=20
r=6 since diameter is a foot or 12 in, half of that is 6
2 (3.14)6×20+2 (3.14)6^2
6.28×6×20+6.28×6^2
753.6+226.08
979.68in
126. first radius= 10
first height = 6
second radius= 6
second height= 10
2 (3.14)10×6+2 (3.14)10^2
6.28×10×6+6.28×10^2
376.8+628
1004.8in (surface area of first cylinder)
2 (3.14)6×10+2 (3.14)6^2
6.28×6×10+6.28×6^2
376.8+226.08
602.88in (surface area of second cylinder)
1004.8-602.88= 401.92
the surface area of the cylinder with radius 10 and height 6 is GREATER that the surface area of the cylinder with radius 6 and height 10..
by 401.92in
Answer: B,C,E
Step-by-step explanation:
The phrases that fit the graph of 
are
- curve positive x-values
- point (1, 1) x-intercept = 0
- quadrant I y-intercept = 0
<h3>How to select the phrases</h3>
The equation of the function is given as:
Next, we plot the graph of the function (see attachment)
From the attached graph, we have the following highlights:
- All points are in quadrant I
- The function is a curve
- It has an x-intercept of x = 0
- It has a y-intercept of y = 0
- It has only positive x values
- It passes through (1,1)
The above represents the phrases that fit the graph
Read more about features of a function at:
brainly.com/question/27771165
#SPJ1
<h3>Complete question</h3>
Using a graphing application, graph y = √x. Sketch the graph below.
Select all phrases that fit the graph of y = √x
curve straight y-intercept = 1 positive x-values
quadrant IV quadrant III point (1, 1) x-intercept = 0
quadrant I y-intercept = 0 no y-intercept negative y-values
no x-intercept quadrant II x-intercept = 1 point (-1, -1)
Answer:
C (x+12)
Step-by-step explanation:
XxX=x^2 12x2=24
Answer:
41 sq. in.
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