<h3>
<u>Answer:</u></h3>
52.38 inch² & 261.90 inch²
<h3>
<u>Step-by-step explanation:</u></h3>
Here we need to find the area of the sector . So according to formula we know the area of sector as ,
Here we can see that the central angle subtended by the arc is 60° and the radius of the circle is 10 inches . So the required area would be ,
=> Area = ∅/ 360° × π r²
=> Area = 60°/360° × 22/7 × (10in.)²
=> Area = 1/6 * 22/7 * 100 in²
=> Area = 52 .380 in²
<h3>
<u>★</u><u> </u><u>Hence </u><u>the </u><u>area </u><u>o</u><u>f </u><u>the </u><u>red</u><u> </u><u>sector </u><u>is </u><u>5</u><u>2</u><u>.</u><u>3</u><u>8</u><u> </u><u>inch²</u><u>.</u></h3>
<u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u>
Now let's find out the area of blue sector .The angle subtended by the arc will be (360-60)°=300° .
=> Area = 300/360 × 22/7 × 100 in²
=> Area = 261. 90 in²
<h3>
<u>★</u><u> </u><u>H</u><u>ence </u><u>the </u><u>area </u><u>of </u><u>blue </u><u>sector </u><u>is </u><u>2</u><u>6</u><u>1</u><u>.</u><u>9</u><u>0</u><u> </u><u>inch</u><u>²</u><u>.</u></h3>


1:30 because in 1 second it beats its wings 30 times
Line a and b are perpendicular
Sloope intercept form is
y=mx+b
m=slope
b=y intercept =where the line passes through the y axis
we are given
line M has slope of 1 and passes through y axis at -2 (y intercept=-2)
equaton is therefor y=1x-2 or y=x-2
line N has slope of 1 and passes through y axis at -2 (y intercept=-2)
equaton is therefor y=1x-2 or y=x-2
compare
line M: y=x-2
line N: y=x-2
they are the same line and lines extend infinitely so therefor there are infinite number of solutions
Answer:
first number= 19/5
second number= 2/5
Step-by-step explanation:
first number= a
second number= b
a+3b=5 equation 1
b+2a=8 equation 2
using equation 2 we have
b=8-2a
using equation 1 we have
a+3(8-2a)=5
a+24-6a=5
24-5=6a-a
19=5a
a=19/5 = first number
so using b=8-2a
we have
b=8-2(19/5)
b=8-(38/5)
b=2/5 = second number