It is given that the scale model of a rectangular garden is 1.5 ft by 4 ft. The scale model is enlarged by a scale factor of 7 to create the actual garden.

Therefore, we can see clearly that the width of the scale model is 1.5 feet. Hence, the width of the actual garden which has been enlarged by a scale factor of 7 will be 7 times the width of the scale model.

Thus the width of the actual garden will be: $1.5\times 7=10.5$ feet

In a similar fashion the length of the actual garden will be $4\times 7=28$ feet

Thus, the area of the actual garden will be:

$Area=Length\times width=10.5\times 28=294$ $ft^2$

As we can see, out of the given options, the last option is the correct one.

6 0

2 years ago

Read 2 more answers

Solve the percent equations 45% of 26=

lara31 [8.8K]

45% = .45
.45 x 26 = 11.7

4 0

3 years ago

The spending at Target is distributed normally with a mean spending of $47.67 and a standard deviation of $5.50. What is the pro

Sphinxa [80]

Answer:

25.10% probability that the spending is between 46 and 49.56 dollars

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 47.67, \sigma = 5.5$