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Lubov Fominskaja [6]
2 years ago
9

Please answer URGENT

Mathematics
1 answer:
aliya0001 [1]2 years ago
8 0
The answer would be 90 because all you do is add the numbers ! (: pls mark me brainliest
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It is 4 1/2 miles to the end of the trail. If Sophia bikes to the end and back in 60 minutes, what is her average speed in miles
PtichkaEL [24]
60 minutes for 2 times of 4.5 miles

60 minutes for 9 miles.

9 miles/60 minutes = 9 miles/1 hour

9 mph
4 0
3 years ago
The graph shows the velocity f(t) of a runner during a certain time interval:
omeli [17]

Answer:

Option B

Step-by-step explanation:

  • (0,2)
  • (6,8)
  • (8,0)

Slope

  • m=8-2/6
  • m=6/6=1

And

  • m=0-8/8-6
  • m=-8/2
  • m=-4

These are acceleration

Y intercept is (0,2) as x coordinate is 0

This is initial velocity 2m/s

The runner stopped at 8s

8 0
2 years ago
-14=6+5x what does x equal
bezimeni [28]
The answer is negative four. subtract six from both sides and you get -20=5x then you would divide both sides by 5 and get -4

7 0
3 years ago
7,14/5, 8/25 find the 7th term
tiny-mole [99]
I believe that would be 7
4 0
3 years ago
The heights of young women aged 20 to 29 follow approximately the N(64, 2.7) distribution. Young men the same age have heights d
murzikaleks [220]

Answer: 10.703%

Step-by-step explanation:

Let minimum height of the tallest 25% of young women be M.

Let Q be the random variable which denotes the height of young women.

Therefore, Q – N(64,2.70)

Now, P(Q˂M) = 1-0.25

i.e. P[(Q-64)/2.7 ˂ (M-64)/2.7] = 0.75

I.e. ф-1 [(M-64)/2.7] = 0.75 i.e. (M-64)/2.7 = ф-1 (0.75) = 0.675 i.e. M = 65.8198 inches

Let R be the random variable denoting the height of young men

Therefore, R – N (69.3, 2.8)

i.e. (R-69.3)/2.8 – N(0,1)

therefore the probability required = P(R ˂65.8198) = P[(R-69.3)/2.8 ˂ (65.8198 – 69.3)/2.8]

this gives P[(R-69.3)/2.8 ˂] = ф (-1.2429) = 0.107033

From this, the percentage of young men shorter than the shortest amongst the tallest 25% of young women is 10.703%

4 0
3 years ago
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