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RoseWind [281]
2 years ago
14

Please Answerrr! I need help ASAPP!

Mathematics
1 answer:
MArishka [77]2 years ago
6 0

80

Step-by-step explanation:

5×6 = 30 and 30×8 = 240 divide that by three you get 80

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F(x)= 20 + 12(x - 2)​
Vinvika [58]

Answer:

f(x) = 12x - 4

Step-by-step explanation:

f(x)= 20 + 12(x - 2)​

Distribute

f(x) =20 +12x - 24

Combine like terms

f(x) = 12x+20-24

f(x) = 12x - 4

4 0
3 years ago
Read 2 more answers
Write and solve a system of equations for this question please
andre [41]
Let b and s be the velocity of the boat and stream respectively....

3(b-s)=27

b-s=9

b=9+s  we will use this in the second equation....

2(b+s)=30

b+s=15, now use b found above in this to get:

9+s+s=15

2s+9=15

2s=6

s=3, and since from earlier b-s=9, b=9+s so

b=12

So the speed of the boat is 12mph and the stream is 3 mph
6 0
3 years ago
Find the slope of the line using the points given (5,3) and (5,-9)
morpeh [17]

Answer:

the slope is undefined

8 0
3 years ago
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Find the equation of the line passing through the points (5,3) and (5,−6).
allsm [11]

Answer:

In y-intercept form: X = 5

Step-by-step explanation:

(\frac{-6-3}{5-5} ) = \frac{-9}{0}

Becuz the slope is Undefined

7 0
3 years ago
The probability that a civil servant own a car is 1/6,if two civil servants are selected at random.find the probability that
Elodia [21]

Answer:

The data we have is:

the probability that a civil servant own a car is 1/6

Two civil servants are selected at random.

a) The probability that each own a car.

Ok, here we have two events:

Person 1 haves a car.

Person 2 haves a car.

The probability of each of those events is the same, 1/6.

P1 = 1/6

P2 = 1/6

Now, the probability of both events happening at the same time is equal to the product of the individual probabilities.

P = P1*P2 = (1/6)*(1/6) = 1/36.

b) Only one has a car.

Suppose that Person 1 has the car and Person 2 has not a car.

The probability for person 1 is 1/6.

And for person 2, is the negation of having a car:

So if we have prob of having a car = 1/6

Then the probability of not having a car is = 1 - 1/6 = 5/6.

Then we have:

P1 = 1/6

P2 = 5/6.

The joint probability is:

P = P1*P2 = (1/6)*(5/6) = 5/36.

But we also have the case where person 1 does not have a car, and person 2 does have one, then we have a permutation, and the actual probability is two times the obtained above.

P = 2*(5/36) = 10/36

4 0
3 years ago
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