Answer:

Step-by-step explanation:
Simply plug in 10 for <em>n</em>
9(1/3)¹⁰⁻¹
9(1/3)⁹
9(1/19683)
9/19683

Unusual notation. I won't fuss with it.
a. We have isosceles PRT, so angle RPT = angle RTP.
By the definition of angle bisector, angle MTP = angle MTF, and angle MPT = angle MPU.
We have m angle RTP = m angle MTF + m angle MTP = 2 m angle MTP
Similarly, m angle RPT = 2 m angle MPT
2 m angle MTP = 2 m angle MPT
angle MPT = angle MPT
That's the first part.
b. That makes MPT isosceles.
c. 2x+124=180
2x = 56
x = 28 degrees
MTP = 28 degrees
d. We have angle RPT=angle RTP=56 so PRT=180-2(56)=68 degrees
PUT = 180 - UTP - UPT = 180 - 28 - 56 = 96 degrees
Bad drawing, PUT looks acute.
angle PRT = 68 degrees, angle PUT = 96 degrees
Arc length has a formula that is similar to arc measure, but arc length is expressed in inches or meters or miles, etc., whereas measure is expressed in degrees, like an angle. The formula for each take this into account. Since the arc length is part of the length of the outside of the circle, the formula includes the circumference for a circle.

, where theta is the degree measure of the central angle intersecting the arc you're looking for, and d is the diameter of the circle. Our formula would look like this with the info we have:

which can be simplified to

which can be simplified even further to

. And that's your answer!
Answer:ed
Step-by-step explanation:
g
Answer:

Step-by-step explanation:

Taking equation (1)

Multiplying both sides by 2

Adding 6y to both sides

Putting this in (2)
5(18+6y) + y = 28
5(18+6y) + y = 28
90 + 30y+y = 28
31y+90-28 = 0
31 y + 62 = 0
31y = -62
Dividing both sides by 31
y = -2
Now,
x = 18 + 6y
x = 18+6(-2)
x = 18-12
x = 6