Ask question

Ask question

All categories

3 years ago

5

The radius of a circle with area A is approximately √A/3. The area of a circular mouse pad is 54 square inches. Estimate its rad

ius to the nearest tenth.

1 answer:

Gnesinka [82]3 years ago

3 0

Answer:

4.2

Step-by-step explanation:

First I did 54 divided by 3 which is 18. Then I found the square root of 18.

You might be interested in

If y varies directly with x and y=20.4 when x=6, find the value of y when x=-5?

a_sh-v [17]

Answer:

y=-17

Step-by-step explanation:

y=mx

20.4=m×6

20.4÷6=m

3.4=m

y=3.4×-5

y=-17

4 0

3 years ago

Read 2 more answers

The length of a rectangle is 3 inches greater than the width.

kati45 [8]

Answer:

A - x (x+3) = Area of the rectangle

B- 28 inches squared

Step-by-step explanation:

B- using the formula from A

x = 4

x + 3 = 4 +3 = 7

4 times 7 is 28

4 0

3 years ago

Read 2 more answers

I need the answer written

padilas [110]

Answer:

x = 180 - (31 + 40)

Step-by-step explanation:

x = 180 - (31 + 40)

5 0

3 years ago

Read 2 more answers

What is the common difference of the arithmetic sequence graphed below?

galben [10]

I think it’s -0.75. The x coordinate represents the term number so y would show the pattern which is -3.75, -4.5, -5.25, -6, -6.75, -7.5, -8.25, -9. To get to the next number, each term is being decreased by 0.75. Hope this helps :)

3 0

3 years ago

Read 2 more answers

Write the equation of a line Parallel to the given line and passes through points (-4, -3); (2, 3). Hints find the slope by usin

julia-pushkina [17]

First, we obtain the gradient (slope) of the first parallel line

$\text{gradient, m}_1\text{ = }\frac{y_2-y_1}{x_2-x_1}\text{ = }\frac{3-(-3)}{2-(-4)}=\frac{6}{6}\text{ = 1}$

Recall that since both lines are parallel, we have that,

$m_1=m_2$

Thus

$m_2\text{ = 1}$

Hence, we can find the equation of the parallel line given that it passes through the points (-4, -3)

Using

$\begin{gathered} y\text{ = mx + c} \\ \text{where m = m}_2\text{ = 1} \\ \text{and x = -4 , y = -3, we have} \\ -3\text{ = 1(-4) + c} \\ -3\text{ = -4 + c} \\ 4\text{ - 3 = c} \\ c\text{ = 1} \\ \text{Thus, the equation of the line is y = (1)x + 1} \\ y\text{ = x + 1} \end{gathered}$

5 0

1 year ago