1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
AlladinOne [14]
3 years ago
5

Recipe calls for 2 1/2 cups flour. i want to make 2/5 of the recipe. how much flour should i use?

Mathematics
1 answer:
WARRIOR [948]3 years ago
6 0
To find the answer ,multiply 2 1/2 by 2/5
(2/5)*(2 1/2)=1
Therefore you should use 1 cup of flour.
You might be interested in
A bakery charges two different prices for desserts. The table shows the number of cupcakes and the number of cookies sold in the
andreev551 [17]

Answer:

hope this helps

Step-by-step explanation:do not need one really

8 0
3 years ago
What is the slope and y-intercept for <br> -6x + 4y = -12
Anestetic [448]
Slope: 3/2
Y-Intercept: -3
6 0
3 years ago
The sector of a circle with a 60 millimeters radius has a central angle measure of 30° . What is the exact area of the sector in
ASHA 777 [7]
R = 60
60^2 * pi = 3600 * pi
angle = 30°
3600pi / 30 = 120pi
the answer is 120 * pi
7 0
3 years ago
100 points , please help. I am not sure if I did this correct if anyone can double-check me thanks!
Nookie1986 [14]

Step-by-step explanation:

\lim_{n \to \infty} \sum\limits_{k=1}^{n}f(x_{k}) \Delta x = \int\limits^a_b {f(x)} \, dx \\where\ \Delta x = \frac{b-a}{n} \ and\ x_{k}=a+\Delta x \times k

In this case we have:

Δx = 3/n

b − a = 3

a = 1

b = 4

So the integral is:

∫₁⁴ √x dx

To evaluate the integral, we write the radical as an exponent.

∫₁⁴ x^½ dx

= ⅔ x^³/₂ + C |₁⁴

= (⅔ 4^³/₂ + C) − (⅔ 1^³/₂ + C)

= ⅔ (8) + C − ⅔ − C

= 14/3

If ∫₁⁴ f(x) dx = e⁴ − e, then:

∫₁⁴ (2f(x) − 1) dx

= 2 ∫₁⁴ f(x) dx − ∫₁⁴ dx

= 2 (e⁴ − e) − (x + C) |₁⁴

= 2e⁴ − 2e − 3

∫ sec²(x/k) dx

k ∫ 1/k sec²(x/k) dx

k tan(x/k) + C

Evaluating between x=0 and x=π/2:

k tan(π/(2k)) + C − (k tan(0) + C)

k tan(π/(2k))

Setting this equal to k:

k tan(π/(2k)) = k

tan(π/(2k)) = 1

π/(2k) = π/4

1/(2k) = 1/4

2k = 4

k = 2

8 0
3 years ago
A spotlight on the ground shines on a wall 12 m away. If a man 2 m tall walks along the x-axis from the spotlight toward the bui
Sedbober [7]

Answer:

0.675 m/s

Step-by-step explanation:

Let height of shadow= y,CD=x

Height of man=2 m

Speed of man= \frac{dx}{dt}=1. 8 m/s

\triangle ABD\sim\triangle ECD

Therefore, \frac{AB}{EC}=\frac{BD}{CD}

\frac{y}{2}=\frac{12}{x}

xy=24

Differentiate w.r.t t

x\frac{dy}{dt}+y\frac{dx}{dt}=0

x\frac{dy}{dt}=-y\frac{dx}{dt}

\frac{dy}{dt}=-\frac{y}{x}\frac{dx}{dt}

When the man is 4 m from  the building

Then, we have x=12-4=8 m

\frac{dx}{dt}=1.8 m/s

Substitute the values in above equation then, we get

8y=24

y=\frac{24}{8}=3

Substitute the values then we get

\frac{dy}{dt}=-\frac{3}{8}\times 1.8=-0.675 m/s

Hence, the length of his shadow on the building decreasing at the rate 0.675 m/s.

8 0
3 years ago
Other questions:
  • Help me help me this is due tomorrow I’m scared!!!
    15·1 answer
  • Find the absolute maximum and absolute minimum values of f on the given interval. f(x) = 6x3 ? 9x2 ? 108x + 2, [?3, 4]
    5·1 answer
  • Explain the distance formula. Then use it to calculate the distance between A(1,1) and B(7,-7).
    14·1 answer
  • A store sells T-shirts for $10 each and jeans for $20 a pair. Anna spends $150 on T-shirts and jeans. She buys x T-shirts and y
    10·2 answers
  • What is the inverse of f(x)=x^4 + 7 for x&gt;0 where function g is the inverse of function f​
    12·1 answer
  • Martin had to buy some cleaning materials.
    13·1 answer
  • PLEASE HELP which best describes the figure that represented by the following coordinates
    9·2 answers
  • What is the value of angle v?
    15·1 answer
  • Find f (3)for f () = 5* - 12.<br> 3<br> 57<br> 113<br> 125
    9·1 answer
  • Help will give brainliest !!! PLEASE ITS EASY
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!