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3 years ago

During sporulation offspring develop from tiny structures called black

Chemistry

2 answers:

Ratling [72]3 years ago

7 0

Answer:

The question is incomplete, here is the correct question.

During sporulation, offspring develop from tiny structures called ______.

The answer is spores.

Explanation:

Sporulation can be described as a process which results in the formation of spores, these spores possess the ability to withstand severe weather conditions. It can also be referred to as the creation of spores by the vegetative cells when the atmospheric condition is not suitable.

Spores are reproductive cells that have the tendency to develop into a new individual without carrying out any form of fusion with an entirely different reproductive cell. Different spores are unaffected by heat and chemicals.

VashaNatasha [74]3 years ago

5 0

Answer:

spores and plant

Explanation:

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Batteries work by letting charged ions flow through an electrolyte solution.

Semmy [17]

Answer:

Batteries work by letting charged ions flow through an electrolyte solution.

A battery is a device that consists of one or more electrochemical cells that can convert stored chemical energy into electrical current. Each cell consists of a positive electrode, or anode, a negative electrode, or cathode, and electrolytes that allow ions to move between the electrodes, allowing current to flow out of the battery to carry out its function.

Explanation:

Its operation is essentially based on a reversible chemical process called reduction-oxidation, in which one of the components is oxidized and the other is reduced; that is, a process whose components are neither consumed nor lost, but merely change their oxidation state, and which in turn can return to their original state under the right circumstances.

4 0

3 years ago

A package of aluminum foil contains 50. ft2 of foil, which weighs approximately 8.5 oz . aluminum has a density of 2.70 g/cm3. w

Serhud [2]

Hello!

We have the following data:

Area (A) = 50 square feet
Mass (m) = 8.5 ounces
Density (d) = 2.70 g/cm³
Volume (V) = ?
Thickness (T) =? (in mm)

To move on, we must transform the area of 50 ft² in cm², let's see:

1 ft² ------- 929,0304 cm²
50 ft² ----- A

$A = 50*929,0304$

$\boxed{A = 46451,52\:cm^2}\Longleftarrow(Area)$

In the same way, we will convert the mass of 8.5 oz in grams, see:

1 oz -------- 28,3495 g
8,5 oz ------- m

$m = 8,5*28,3495$

$\boxed{m = 240,97075\:g}\Longleftarrow(mass)$

Knowing that the density is 2.70 g/cm³ and the mass is 240.97075 g, we will find the volume, applying the data in the density formula we have:

$d = \dfrac{m}{V} \to V = \dfrac{m}{d}$

$V = \dfrac{240,97075\:\diagup\!\!\!\!\!g}{2,70\:\diagup\!\!\!\!\!g/cm^3}$

$V = 89,24842593... \to \boxed{V \approx 89,25\:cm^3}$

The statement wants to find the thickness of the packaging, for this we have some important data, such as: V (volume) = 89,25 cm³ and Area (A) = 46451,52 cm² and T (thickness) =? (in mm)

In the calculations of Costs in Surface Treatment of a part within the flat geometry, we will use the following formula:

$V (volume) = A (Area) * T (Thickness)$

$89,25\:cm^3 = 46451,52\:cm^2\:*\:T$

$46451,52\:cm^2*T = 89,25\:cm^3$

$T = \dfrac{89,25\:cm^3}{46451,52\:cm^2}$

$T = 0,001921358009...\:cm$

We will convert to millimeters, going through a decimal place on the right

$T = 0,01921358009..\:mm$

$\boxed{\boxed{T \approx 0,0192\:mm\:or\:T\approx \:1,92*10^{-2}\:mm}}\end{array}}\Longleftarrow(thickness)\qquad\checkmark$

Hope this helps! :))

8 0

3 years ago

Guys if you help me and I got a right I will Mark you BRAINLIEST >:DDDDDDDD

Alik [6]

Answer:

d..i think..he found plant cells

Explanation:

7 0

3 years ago

Read 2 more answers

How far is 150 kilometers in 2 hours

Lisa [10]