AgNO3(aq) + KCl (aq)-----> AgCl(s) + KNO3(aq)

Ag ^+(aq) + NO3^-(aq) + K^+ (aq) + cl^- (aq) ----> AgCl(s) + K^+(aq) + NO3^-(aq)

net ionic equation
Ag ^+(aq) + Cl^-(aq) ----> AgCl(s)

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3 years ago

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19) What is the molarity of a KOH solution if 200 ml of the solution contains 0.6 moles KOH?

zloy xaker [14]

Answer: 3M

Explanation: Molarity : It is defined as the number of moles of solute present in one liter of solution.

Formula used :

$Molarity=\frac{n\times 1000}{V_s}$

where,

n = moles of solute $KOH$ = 0.6 moles

$V_s$ = volume of solution in ml= 200 ml

Now put all the given values in the formula of molarity, we get

$Molarity=\frac{0.6moles\times 1000}{200ml}=3mole/L$

Therefore, the molarity of solution will be 3M.

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3 years ago

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