Answer: V2= 15.0403226 Liters
Explanation:
Use V1/T1=V2/T2
Make sure you change the degrees Celsius to Kelvin. (Kelvin = degrees Celsius +273)
10.0L / 248 K = V2/ 373 K
Cross multiply V1 and T2 and divide by T1
(10.0 L)( 373K)/ 248 K = V2
V2= 15.0403226 Liters (Kelvin cancels out)
Answer : The number of moles of HCl neutralize is, 0.00824 moles.
Explanation :
The given balanced chemical reaction is:

First we have to calculate the moles of 

Molar mass of
= 144 g/mol

Now we have to calculate the moles of HCl.
From the balanced chemical reaction we conclude that,
As, 1 mole of
react with 4 moles of HCl
So, 0.00206 mole of
react with
moles of HCl
Thus, the number of moles of HCl neutralize is, 0.00824 moles.
Answer:
See explanation
Explanation:
The nucleophile here is CH3OH. We know that CH3OH is a good nucleophile that promotes SN2 reanction. However, (R)-6-bromo-2,6-dimethylnonane is a tertiary alkyl halide so the reaction proceeds by SN1 mechanism. This means that a racemic mixture is obtained at the end of the reaction because the attack occurs at the stereogenic carbon atom (6R) hence the product is optically inactive.
On the other hand, when (5R)-2-bromo-2,5-dimethylnonane is reacted with CH3OH, an optically active product is obtained because; though a tertiary alkyl halide and reaction occurs by SN1 mechanism, the attack does not occur at the stereogenic carbon atom (5R). Therefore, an optically active product is obtained in this case.
<u>Answer:</u> The salinity of ocean water is 34 ppt.
<u>Explanation:</u>
Salinity is defined as the number of grams of salts present per kilogram of seawater. It is expressed in parts per thousand.
The formula used to calculate the salinity of ocean water or sea water is:

We are given:
Mass of salts = 17 g
Mass of sea water = 500 g
Putting values in above equation, we get:

Hence, the salinity of ocean water is 34 ppt.
Answer: the sugar ge hotter??
Explanation: