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kobusy [5.1K]
3 years ago
14

Ethanol (c2h5oh) burns according to the equation c2h5oh(l) + 3o2(g) â 2co2(g) + 3h2o(l), δh= -1367 kj/mol. how much heat is rel

eased when 35.0 g of ethanol is burned?
Chemistry
1 answer:
Eva8 [605]3 years ago
6 0
Molar mass of ethanol is: 46 grams/moles
C2H6O-> 2x12 + 6x1+ 16x1      (see periodic table)

If 46 g correspond to 1 mol, how much moles correspond 35 g?
46g ====1mol
35g====x
x= 35/46
x=0,76 mol

-1367 kj/mol, means that there are -1367 kj in one mol
1mol     ==== -1367 kj
0,76mol====  x
x=- 1040Kj


Ethanol released 1040 Kj.




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Answer: V2= 15.0403226 Liters

Explanation:

Use V1/T1=V2/T2

Make sure you change the degrees Celsius to Kelvin. (Kelvin = degrees Celsius +273)

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Cross multiply V1 and T2 and divide by T1

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4 0
3 years ago
An old antacid commercial claimed that each tablet of their product could neutralize 47 times its mass in stomach acid. The acti
butalik [34]

Answer : The number of moles of HCl neutralize is, 0.00824 moles.

Explanation :

The given balanced chemical reaction is:

NaAl(OH)_2CO_3+4HCl\rightarrow NaCl+AlCl_3+3H_2O+CO_2

First we have to calculate the moles of NaAl(OH)_2CO_3

\text{Moles of }NaAl(OH)_2CO_3=\frac{\text{Mass of }NaAl(OH)_2CO_3}{\text{Molar mass of }NaAl(OH)_2CO_3}

Molar mass of NaAl(OH)_2CO_3 = 144 g/mol

\text{Moles of }NaAl(OH)_2CO_3=\frac{0.296g}{144g/mol}=0.00206mol

Now we have to calculate the moles of HCl.

From the balanced chemical reaction we conclude that,

As, 1 mole of NaAl(OH)_2CO_3 react with 4 moles of HCl

So, 0.00206 mole of NaAl(OH)_2CO_3 react with 0.00206\times 4=0.00824 moles of HCl

Thus, the number of moles of HCl neutralize is, 0.00824 moles.

8 0
3 years ago
When (R)-6-bromo-2,6-dimethylnonane is dissolved in CH3OH, nucleophilic substitution yields an optically inactive solution. When
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Answer:

See explanation

Explanation:

The nucleophile here is CH3OH. We know that CH3OH is a good nucleophile that promotes SN2 reanction. However, (R)-6-bromo-2,6-dimethylnonane is a tertiary alkyl halide so the reaction proceeds by SN1 mechanism. This means that a racemic mixture is obtained at the end of the reaction because the attack occurs at the stereogenic carbon atom (6R) hence the product is optically inactive.

On the other hand, when (5R)-2-bromo-2,5-dimethylnonane is reacted with CH3OH, an optically active product is obtained because; though a tertiary alkyl halide and reaction occurs by SN1 mechanism, the attack does not occur at the stereogenic carbon atom (5R). Therefore, an optically active product is obtained in this case.

7 0
3 years ago
Suppose that you take a sample of 500 g of ocean water and let the water evaporate. The mass of the remaining salts is 17 g. Wha
yanalaym [24]

<u>Answer:</u> The salinity of ocean water is 34 ppt.

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We are given:

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Putting values in above equation, we get:

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Hence, the salinity of ocean water is 34 ppt.

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