Answer:
60 inches long are the sides of the pillars.
Step-by-step explanation:
Given : A small bridge sits atop four cube shaped pillars that all have the same volume. the combined volume of the four pillars is 500 ft cubed.
To find : How many inches long are the sides of the pillars?
Solution :
Refer the attached picture below for Clarence of question.
The volume of the cube is 
Where, a is the side.
The combined volume of the four pillars is 500 ft cubed.
The volume of each cube is given by,
Substitute in the formula to get the side,
![a=\sqrt[3]{125}](https://tex.z-dn.net/?f=a%3D%5Csqrt%5B3%5D%7B125%7D)
We know, 1 feet = 12 inches
So, 5 feet =
inches
Therefore, 60 inches long are the sides of the pillars.
<u><em>Answer:</em></u>
The height of the parallelogram is 33 ft
<u><em>Explanation:</em></u>
<u>The area of the parallelogram can be calculated using the following rule:</u>
Area of parallelogram = base * height
<u>In the problem, we are given that:</u>
Area = 544.5 ft²
Base = 16.5 ft
<u>Substitute with the given values in the above equation and solve for the height as follows:</u>
Area = base * height
544.5 = 16.5 * height
Hope this helps :)
With 4 jacks in the deck of 52, there is a 4/52 = 1/13 probability of drawing 1 jack.
With 13 clubs in the deck, there is a 13/52 = 1/4 probability of drawing 1 card of clubs.
1 of the cards in the deck is both a jack and of suit of clubs, which has a 1/52 probability of being drawn.
P(club OR jack) = P(club) + P(jack) - P(club AND jack) = 13/52 + 4/52 - 1/52 = 16/52 = 4/13
So the answer is B.
