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NNADVOKAT [17]
3 years ago
7

What strategy am I suppose to use??

Mathematics
2 answers:
icang [17]3 years ago
7 0

Answer:

Just find a pattern. In this instance, every number increases by one less than the previous increase.

Step-by-step explanation:

For example, 2 increases by 8 to 10. Then it increases by 7 to get to 17. Then it increases by 6, then by 5, and it will continue in that way for the next two, increasing by 4 to get 32, and then increasing by 3 to get to 35.

olga55 [171]3 years ago
5 0

2,10,17,23,28,32,35

=> the next numbers are 28+4 = 32, and 32+3 = 35

a1 = 2

a2 = a1+8

a3 = a2+7

a4 = a3+6

a5 = a4+5

a6 = a5+4

a7 = a4+3

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3 years ago
Explain the steps in finding the midpoint of the points (-1,2) and (3,-6). The state the midpoint
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(1, -2)

Step-by-step explanation:

midpoint x = (x₁ + x₂) / 2

midpoint y = (y₁ + y₂) / 2

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(3 marks) A certain type of storage battery lasts, on average, 3.0 years with a standard deviation of 0.5 year. The battery live
Ksenya-84 [330]

Answer:

0.8041 = 80.41% probability that a given battery will last between 2.3 and 3.6 years

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

A certain type of storage battery lasts, on average, 3.0 years with a standard deviation of 0.5 year

This means that \mu = 3, \sigma = 0.5

What is the probability that a given battery will last between 2.3 and 3.6 years?

This is the p-value of Z when X = 3.6 subtracted by the p-value of Z when X = 2.3. So

X = 3.6

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Z = \frac{3.6 - 3}{0.5}

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Z = -1.4 has a p-value of 0.0808

0.8849 - 0.0808 = 0.8041

0.8041 = 80.41% probability that a given battery will last between 2.3 and 3.6 years

4 0
2 years ago
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Yuliya22 [10]
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