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Crazy boy [7]
3 years ago
8

Write a system of linear equations for the graph below

Mathematics
1 answer:
Goshia [24]3 years ago
7 0

Answer:

\left \{{{y=3-\frac{x}{3} }\atop { y=-2x-2}} \right.

Step-by-step explanation:

(-3,4),(0,3)\\y=3-\frac{x}{3} \\(-3,4),(0,-2)\\\\y=-2x-2

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School A has graduated 1,700 students and graduates
Alisiya [41]

Answer:

the answer is 11 years

Step-by-step explanation:

if school A is graduated 50/years,

the graduated in 11 years is 550

added of graduated 1,700 in 550 is 2,250

if school B is graduated 150/years,

the graduated in 11 years is 1650

added of graduated 600 in 1650 is 2,250

so School A and B is to be equal in 11 years

4 0
3 years ago
Solve the system using elimination: -3x - 3y = 12 -9x + 3y = -24<br><br>The answer is not (-1,-3)
FinnZ [79.3K]

Answer:

{x = 1, y = -5

Step-by-step explanation:

Solve the following system:

{-3 x - 3 y = 12 | (equation 1)

{3 y - 9 x = -24 | (equation 2)

Swap equation 1 with equation 2:

{-(9 x) + 3 y = -24 | (equation 1)

{-(3 x) - 3 y = 12 | (equation 2)

Subtract 1/3 × (equation 1) from equation 2:

{-(9 x) + 3 y = -24 | (equation 1)

0 x - 4 y = 20 | (equation 2)

Divide equation 1 by 3:

{-(3 x) + y = -8 | (equation 1)

{0 x - 4 y = 20 | (equation 2)

Divide equation 2 by 4:

{-(3 x) + y = -8 | (equation 1)

{0 x - y = 5 | (equation 2)

Multiply equation 2 by -1:

{-(3 x) + y = -8 | (equation 1)

{0 x+y = -5 | (equation 2)

Subtract equation 2 from equation 1:

{-(3 x)+0 y = -3 | (equation 1)

{0 x+y = -5 | (equation 2)

Divide equation 1 by -3:

{x+0 y = 1 | (equation 1)

{0 x+y = -5 | (equation 2)

Collect results:

Answer:  {x = 1 , y = -5

5 0
4 years ago
What are the coordinates of the midpoint of the segment whose endpoints are A(−1, 9) and B(3, 8) ?
Mrrafil [7]
\bf \textit{middle point of 2 points }\\ \quad \\&#10;\begin{array}{lllll}&#10;&x_1&y_1&x_2&y_2\\&#10;%  (a,b)&#10;A&({{ -1}}\quad ,&{{ 9}})\quad &#10;%  (c,d)&#10;B&({{ 3}}\quad ,&{{ 8}})&#10;\end{array}\qquad&#10;%   coordinates of midpoint &#10;\left(\cfrac{{{ x_2}} + {{ x_1}}}{2}\quad ,\quad \cfrac{{{ y_2}} + {{ y_1}}}{2} \right)&#10;\\\\\\&#10;\left(\cfrac{{{ 3}} - {{ 1}}}{2}\quad ,\quad \cfrac{{{ 8}} + {{ 9}}}{2} \right)
3 0
4 years ago
Does anyone know the answer?<br><br> -9x+1=80<br><br> and <br><br> -2=2+v/4
lara [203]

Answer:

-9x+1= to -8

and -2=2=v/4= to 5.e-1

Step-by-step explanation:

I hope that you get it right!!

this is my opinion

6 0
4 years ago
Solve the inequality.<br><br> 16p+3) &gt; 15
EastWind [94]

Answer:

16p + 3 > 15

16p > 15 - 3

16p > 12

p > 12/16

p > 3/4

p ∈ (3/4 ; + oo)

4 0
3 years ago
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