Since the average height is 60 inches and its deviation is 2 inches, one deviation to the right (or higher) is 62 inches (60 + 2). Two deviations is 64 inches, three deviations is 66 inches, and four deviations is 68 inches.
Since the average weight is 100 pounds and its deviation is 5 inches, we repeat the process from finding heights to get to 115 pounds. That takes three deviations.
The MORE deviations away, the more unusual it is. So the height (4 deviations) is more unusual than the weight (3 deviations).
its all about the angles just subtract the number you have from the total
Answer:

Step-by-step explanation:
<u>Given function is:</u>

Put x = 4
So,
![f(4) = 4^4\\\\f(4) = 256\\\\\rule[225]{225}{2}](https://tex.z-dn.net/?f=f%284%29%20%3D%204%5E4%5C%5C%5C%5Cf%284%29%20%3D%20256%5C%5C%5C%5C%5Crule%5B225%5D%7B225%7D%7B2%7D)
Hope this helped!
<h3>~AH1807</h3>
Gggggggggggggggggggggggggggggggggggggg. It would be 7
Answer:
a) 151lb.
b) 6.25 lb
Step-by-step explanation:
The Central Limit Theorem estabilishes that, for a random variable X, with mean
and standard deviation
, a large sample size can be approximated to a normal distribution with mean
and standard deviation
.
In this problem, we have that:

So
a) The expected value of the sample mean of the weights is 151 lb.
(b) What is the standard deviation of the sampling distribution of the sample mean weight?
This is 