All categories

2 years ago

I am stuck on these last four questions please help if possible.

Mathematics

1 answer:

zloy xaker [14]2 years ago

4 0

Answer:

Step-by-step explanation:

9). -2.2(4 - 1.9x) = 3.3(0.2x - 0.8)

-8.8 + 2.2(1.9x) = 0.66x - 2.64

-8.8 + 4.18x = 0.66x - 2.64

4.18x - 0.66x = 8.8 - 2.64

3.52x = 6.16

x = 1.75

10). 3.2(1 + 2.6x) = 2.4(x - 3.6)

3.2 + 8.32x = 2.4x - 8.64

8.32x - 2.4x = -3.2 - 8.64

5.92x = -11.84

x = 2

11). 4.6(2x - 5.5) = 3.9 + 0.8(1 + 5.5x)

9.2x - 25.3 = 3.9 + 0.8 + 4.4x

9.2x - 25.3 = 4.7 + 4.4x

9.2x - 4.4x = 25.3 + 4.7

4.8x = 30

x = 6.25

12). 0.2(3x + 2.5) - 4.9 = 3.8 - 2.2(x - 5.5)

0.6x + 0.5 - 4.9 = 3.8 - 2.2x + 12.10

0.6x - 4.4 = -2.2x + 15.90

0.6x + 2.2x = 15.90 + 4.4

2.8x = 20.30

x = 7.25

You might be interested in

Brian, Pip and Sara share some sweets in the ratio 4:2:1. Brian gets 45 more sweets than Sara. How many sweets are there altoget

elixir [45]

Answer:

105 sweets

Step-by-step explanation:

4×15 = 60

2×15=30

1×15=15

60-15 =45

60+30+15=105

5 0

2 years ago

A reading teacher recorded the number of pages read in an hour by each of her

Ymorist [56]

Answer:

the lower quartile should be 43.5, not 44, therefore the 3 is the wrong statistic

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Plz help

Len [333]

52x38=1976, 1976 is the answer

5 0

3 years ago

A savings and loan association needs information concerning the checking account balances of its local customers. A random sampl

Marina86 [1]

Answer:

The 99% confidence interval for the true mean checking account balance for local customers is ($439.29, $888.99).

Step-by-step explanation:

We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 14 - 1 = 13

99% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 13 degrees of freedom(y-axis) and a confidence level of $1 - \frac{1 - 0.99}{2} = 0.995$ . So we have T = 3.0123

The margin of error is:

$M = T\frac{s}{\sqrt{n}} = 3.0123\frac{279.29}{\sqrt{14}} = 224.85$

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 664.14 - 224.85 = $439.29

The upper end of the interval is the sample mean added to M. So it is 664.14 + 224.85 = $888.99.

The 99% confidence interval for the true mean checking account balance for local customers is ($439.29, $888.99).

4 0

3 years ago

What is the range of this graph

Arlecino [84]

Answer:

[0,12]

Step-by-step explanation:

7 0

3 years ago