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Genrish500 [490]

3 years ago

9

Write an equation of the line that passes through the given point and is parallel to the given line. Please help!!

1 answer:

Inessa05 [86]3 years ago

8 0

Answer: C y= -3/2x + 11

Step-by-step explanation:

So you have to know the parallel lines have the same slopes but different y- intercepts. so we will use the same slopes but we will calculate the y -intercept.

in the points (4,5) 5 is the y value and 4 is the x value. and we will plot it into the formula y=mx + b where m is the slope and we already know the slope is -3/2 but we need to find the y intercept.

5 = -3/2(4) + b

5= -6 + b

+6 +6

b= 11 so now we know the y intercept is 11 so the equation will be y= -3/2x + 11

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What are the coordinates of the circumcenter of this triangle?

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The coordinates of the circumcenter of this triangle are (3,2)

Step-by-step explanation:

we know that

The circumcenter is the point where the perpendicular bisectors of a triangle intersect

we have the coordinates

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step 1

Find the midpoint AB

The formula to calculate the midpoint between two points is equal to

$M=(\frac{x1+x2}{2},\frac{y1+y2}{2})$

substitute the values

$M=(\frac{-2-2}{2},\frac{5-1}{2})$

$M_A_B=(-2,2)$

step 2

Find the equation of the line perpendicular to the segment AB that passes through the point (-2,2)

Is a horizontal line (parallel to the x-axis)

$y=2$ -----> equation A

step 3

Find the midpoint BC

The formula to calculate the midpoint between two points is equal to

$M=(\frac{x1+x2}{2},\frac{y1+y2}{2})$

substitute the values

$M=(\frac{-2+8}{2},\frac{-1-1}{2})$

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step 4

Find the equation of the line perpendicular to the segment BC that passes through the point (3,-1)

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step 5

Find the circumcenter

The circumcenter is the intersection point between the equation A and equation B

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The intersection point is (3,2)

therefore

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