Please help asap! its needed badly

HELP PLEASEEEE THERES PICCTURESSS

LenKa [72]

I hate school so much <3

4 0

2 years ago

Read 2 more answers

What is the volume of the following prism?

ira [324]

Answer: $\Large\boxed{B.~\displaystyle 75~m^3}$

Step-by-step explanation:

<u>Given information</u>

Height = 2 m

Base = 5 m

Length = 15 m

<u>Given the formula for Triangular Prism Volume</u>

$V~=~\displaystyle \frac{1}{2}\times ~b~\times~h~\times~l$

$\to V=Volume\\\to b=base\\\to h = height\\\to l = length$

<u>Substitute values into the formula</u>

$V~=~\displaystyle \frac{1}{2}\times ~(5)~\times~(2)~\times~(15)$

<u>Simplify by multiplication</u>

$V~=~\displaystyle \frac{5}{2}~\times ~30$

$\Large\boxed{V~=~\displaystyle 75~m^3}$

Hope this helps!! :)

Please let me know if you have any questions

3 0

1 year ago

Find the z-score boundaries that separate a normal distribution as described in each of the following. a. The middle 20% from th

Anna007 [38]

Answer:

a) The boundaries are $Z = \pm 0.253$

b) The boundaries are $Z = \pm 0.675$ .

c) The boundaries are $Z = \pm 1.96$ .

d) The boundaries are $Z = \pm 2.575$ .

Step-by-step explanation:

Z-score:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

a. The middle 20% from the 80% in the tails.

The middle 20% is between the 50 - (20/2) = 40th percentile and the 50 + (20/2) = 60th percentile:

40th percentile: Z has a pvalue of 0.4, so Z = -0.253.

60th percentile: Z has a pvalue of 0.6, so Z = 0.253.

The boundaries are $Z = \pm 0.253$ .

b. The middle 50% from the 50% in the tails.

The middle 50% is between the 50 - (50/2) = 25th percentile and the 50 + (50/2) = 75th percentile:

25th percentile: Z has a pvalue of 0.25, so Z = -0.675.

75th percentile: Z has a pvalue of 0.75, so Z = 0.675.

The boundaries are $Z = \pm 0.675$ .

c. The middle 95% from the 5% in the tails.

The middle 95% is between the 50 - (95/2) = 2.5th percentile and the 50 + (95/2) = 97.5th percentile:

2.5th percentile: Z has a pvalue of 0.025, so Z = -1.96.

97.5th percentile: Z has a pvalue of 0.975, so Z = 1.96.

The boundaries are $Z = \pm 1.96$ .

d. The middle 99% from the 1% in the tails.

The middle 99% is between the 50 - (99/2) = 0.5th percentile and the 50 + (99/2) = 99.5th percentile:

0.5th percentile: Z has a pvalue of 0.005, so Z = -2.575.

99.5th percentile: Z has a pvalue of 0.995, so Z = 2.575.

The boundaries are $Z = \pm 2.575$ .

6 0

3 years ago

Simplify 4.51^0 - which is it?<br> 4.51 ?<br> 1 ?<br> 0 ?<br> -1 ?

koban [17]

Answer:

$1$

Step-by-step explanation:

${(4.51) }^{0} = 1$

hope this helps you.

5 0

4 years ago

Brandy solved 1/6/ 5 using a related multiplication expression. What multiplication expression did she use?

Advocard [28]

<h3><u>Question:</u></h3>

Brandy solved 1/6÷ 5 by using a related multiplication expression. which multiplication expression did she use

<h3><u>Answer:</u></h3>

The expression that she can use is $\frac{1}{6} \times \frac{1}{5}$

<h3><u>Solution:</u></h3>

<em><u>Given that Brandy solved the following expression</u></em>

$\frac{1}{6} \div 5$

We have to find the multiplication expression she used

From given expression,

$\frac{1}{6} \div 5$

We can convert the division symbol to multiplication

Convert the fraction division process to a multiplication process by using the following steps:

Change the “÷” (division sign) to “x” (multiplication sign) and invert the number to the right of the sign.

Multiply the numerators. Multiply the denominators

Therefore,

$\frac{1}{6} \div 5 = \frac{1}{6} \times \frac{1}{5}$

$\frac{1}{6} \div 5 = \frac{1}{6} \times \frac{1}{5} = \frac{1}{30}$

Thus, the expression that she can use is $\frac{1}{6} \times \frac{1}{5}$

5 0

3 years ago