Question

The sum of two positive integers is 12. When the smaller integer is subtracted from five times the larger, the result is 36. Find the two integers.

Answer 1

Answer:

The smaller integer is 4 and larger integer is 8 .

Step-by-step explanation:

First we have to form own variables and expression. So we let the smaller integer be x and the larger integer be y. Next using the information given to form expressions :

$x + y = 12 \\ 5y - x = 36$

Lastly, we can solve the simultaneous equation using Elimination :

$x + y = 12 - - - (1)$

$- x + 5y = 36 - - - (2)$

$(1) + (2)$

$x + ( - x) + y + 5y = 12 + 36$

$6y = 48$

$y = 8$

$sub \: y = 8 \: into \: (1)$

$x + 8 = 12$

$x = 4$