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3 years ago

Solve a=2pir^2 2pirh for pi

1 answer:

7 0

A = 2 $\pi$ $r^{2}$ 2 $\pi$ rh |Divide by 4h $r^{3}$

$\pi ^{2}$ = $\frac{a}{4h r^{3} }$ |Square root on both sides

$\pi$ = $\sqrt{ \frac{a}{4h r^{3} } }$

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F(x) = 2x g(x) = x + 5 h(X) = 3x - 7 What is the correct set up for h(f(x))?? *

Usimov [2.4K]

Answer:

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Jacob is working two summer jobs, making $10 per hour washing cars and making $8 per hour landscaping. In a given week, he can w

Burka [1]

Answer:

Step-by-step explanation:

Let x represent the number of hours that that he spent washing cars.

Let y represent the number of hours that that he spent landscaping.

In a week, he can work no more than 19 total hours. This means that

x + y ≤ 19- - - - - - - - - - - -1

Jacob is working two summer jobs, making $10 per hour washing cars and making $8 per hour landscaping. He must earn at least $170. This means that

10x + 8y ≥ 170 - - - - - - - - - -2

If Jacob worked 4 hours landscaping, it means that

x + 4 ≤ 19

x ≤ 19 - 4

x ≤ 15

Also,

10x + 8 × 4 ≥ 170

10x + 32 ≥ 170

10x ≥ 170 - 32

10x ≥ 138

10x ≥ 138/10

x ≥ 13.8

The minimum number of hours is 14

6 0

3 years ago

The work W required to move a particle from a far distance to within radius r of another particle varies jointly as the product

tangare [24]

Answer:

W = kq1q2 / r

Step-by-step explanation:

W varies jointly as the product of q1 and q2 and inversely as radius r

Product of q1 and q2 = q1q2

W = (k*q1"q2) / r

W = kq1q2 / r

Where,

W = work

q1 = particle 1

q2 = particle 2

r = radius

k = constant of proportionality

The answer is W = kq1q2 / r

5 0

3 years ago

Kent and Bradley both work at a car dealership. Kent makes $10/hour + 3% on the amount of sales he completes. Bradley only makes

Masteriza [31]

Answer: There is difference of $660 in their paychecks.

Step-by-step explanation:

Since we have given that

Number of hours in one week they worked = 40

Amount of sales = $78000

Kent makes $10 per hour plus 3% on the amount of sales .

So, the equation for Kent becomes,

$10\times 40+\frac{3}{100}\times 78000\\\\=400+3\times 780\\\\=400+2340\\\\=\$2740$

Similarly, Bradley only makes $7 per hour but he makes 4% on the amount of his sales .

So, the equation for Bradley becomes,

$7\times 40+\frac{4}{100}\times 78000\\\\=280+4\times 780\\\\=280+3120\\\\=\$3400$

hence, the difference between of their paychecks is given by

$\$3400-\$2740\\\\=\$660$

Therefore, there is difference of $660 in their paychecks.

3 0

2 years ago

The school that Mary goes to is selling tickets to a spring musical. On the first day of ticket sales

andrezito [222]

Answer:

The cost of one adult ticket is $13, and the price of one student ticket is $4.

Step-by-step explanation:

This question can be solved using a system of equations.

I am going to say that:

x is the cost of an adult ticket

y is the cost of a student ticket.

6 adult tickets and 1 student ticket for a total of $82

This means that

$6x + y = 82$

$y = 82 - 6x$

The school took in $51 on the second day by selling 3 adult tickets and 3 student tickets.

This means that

$3x + 3y = 51$

Simplifying by 3

$x + y = 17$

Since $y = 82 - 6x$

$x + 82 - 6x = 17$

$-5x = -65$

$5x = 65$

$x = \frac{65}{5} = 13$

$y = 82 - 6x = 82 - 6*13 = 82-78 = 4$

The cost of one adult ticket is $13, and the price of one student ticket is $4.

4 0

3 years ago