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attashe74 [19]
3 years ago
12

Solve a=2pir^2 2pirh for pi

Mathematics
1 answer:
MrRa [10]3 years ago
7 0
A = 2\pi r^{2} 2\pirh   |Divide by 4hr^{3}

\pi ^{2} = \frac{a}{4h r^{3} }          |Square root on both sides

\pi = \sqrt{ \frac{a}{4h r^{3} } }

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Shota invests $1000 in a certificate of deposit that earns interest. The investment’s value is multiplied by 1.02 each year. Whi
DENIUS [597]

Answer:

1020

Step-by-step explanation:

1000 times 1.02

here the answer will be 1020.

step-by-step explanation:

1000 times 1.02= 1020

5 0
4 years ago
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Peanuts are $2 a pound and raisins are $4 a pound. Julian bought a 7 pound mixture of peanuts and raisins for $20. How many poun
Elena-2011 [213]

Answer:

there was 3 pounds of raisins and 4 pounds peanuts.

Step-by-step explanation:

4 times 3 =12 and 2 times 4 = 8. 3+4=7 so 7 pounds. 12+8=20 so $20.

4 0
3 years ago
Tyler went to the supermarket to buy food for a food pantry. He has $36, and can carry up to 20 pounds of food in his backpack.
sattari [20]

Answer:

Solutions: (2,10), (4,5)

Not solutions: (1,12), (6,10), (12,8), (18,6)

Step-by-step explanation:

Let x be the number of packages of pasta and y be the number of jars of pasta sauce. If pasta costs $1 for a 1-pound package, then x packages of pasta cost $x and weigh x pounds. If pasta sauce costs $3 for a 1.5 pound jar, then y jars cost $3y and weigh 1.5y pounds.

1. Tyler has $36, then

x+3y\le 36.

2. Tyler can carry up to 20 pounds of food in his backpack, then

x+1.5y\le 20.

You get the following system of inequalities:

\left\{\begin{array}{l}x+3y\le 36\\ x+1.5y\le 20\end{array}\right.

Now substitute the coordinates of each point:

<u>(1,12):</u>

\left\{\begin{array}{l}1+3\cdot 12=37> 36\\ 1+1.5\cdot 12=19\le 20\end{array}\right.

False, because first inequality doesn't hold.

<u>(2,10):</u>

\left\{\begin{array}{l}2+3\cdot 10=32\le 36\\ 2+1.5\cdot 10=17\le 20\end{array}\right.

True, both inequalities hold.

<u>(4,5):</u>

\left\{\begin{array}{l}4+3\cdot 5=19\le 36\\ 4+1.5\cdot 5=11.5\le 20\end{array}\right.

True, both inequalities hold.

<u>(6,10):</u>

\left\{\begin{array}{l}6+3\cdot 10=36\le 36\\ 6+1.5\cdot 10=21> 20\end{array}\right.

False, because secondt inequality doesn't hold.

<u>(12,8):</u>

\left\{\begin{array}{l}12+3\cdot 8=36\le 36\\ 12+1.5\cdot 8=24> 20\end{array}\right.

False, because second inequality doesn't hold.

<u>(18,6):</u>

\left\{\begin{array}{l}18+3\cdot 6=36\le 36\\ 18+1.5\cdot 6=27> 20\end{array}\right.

False, because second inequality doesn't hold.

7 0
3 years ago
How many significant figures are there in the following measurement?2.04679 millimeters
BARSIC [14]
6 because if you take the 2.04679 then divide you would get 6.
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3 years ago
Helpp I don't understand
pychu [463]

Answer:

the answer is C or 18x + 18y

6 0
3 years ago
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