All categories

3 years ago

Can I get help please.

Mathematics

1 answer:

scoundrel [369]3 years ago

4 0

Answer:

see below

Step-by-step explanation:

A: Points A and B form a right triangle with legs of 2 and 5 so AB is approximately 5.4 from the Pythagorean Theorem.

B: Points B and C form a right triangle with legs of 2 and 5 so BC is approximately 5.4.

C: We need to find the length of AC. We can do this by using the same strategy above. Points A and C form a right triangle with legs of 7 and 3 so AC = 7.6. To find the perimeter we'll do 5.4 + 5.4 + 7.6 = 18.4.

You might be interested in

PLEASE HELP FAST! Solve for Y in the following system of equations!

victus00 [196]

Answer:

B.) 3

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Algebra I

Solving systems of equations using substitution/elimination

Step-by-step explanation:

Step 1: Define Systems

x - y = -1

3x + 5y = 21

Step 2: Rewrite Systems

x - y = -1

Add y to both sides: x = y - 1

Step 3: Redefine Systems

x = y - 1

3x + 5y = 21

Step 4: Solve for y

Substitution

Substitute in x: 3(y - 1) + 5y = 21
Distribute 3: 3y - 3 + 5y = 21
Combine like terms: 8y - 3 = 21
Add 3 to both sides: 8y = 24
Divide 8 on both sides: y = 3

7 0

3 years ago

Whitch is greater -8 or +8

finlep [7]

+8 is the greatest then -8

8 0

3 years ago

Read 2 more answers

7/7q+21= x /5q^2-45 then x=?

anzhelika [568]

Answer:

x = 5q - 15

Step-by-step explanation:

$\frac{7}{7q+21}=\frac{x}{5q^{2}-45}\\\\\frac{7}{7(q+3)}=\frac{x}{5 (q^{2} -9)}\\\\frac{1}{q+3}=\frac{x}{5*(q^{2}-3^{2})}\\\\\frac{1}{q+3}=\frac{x}{5(q+3)(q-3)}\\\\\frac{1}{q+3}*5*(q+3)(q-3)=x\\\\5(q-3)=x\\\\x= 5q-15$

3 0

3 years ago

14x+2y=-10 solve equations for y

Ne4ueva [31]

Answer:

y = -7x - 5

Step-by-step explanation:

14x + 2y = -10

2y = -14x - 10

2y/2 = -14x/2 - 10/2

y = -7x - 5

Hope this helps -w-

3 0

3 years ago

Read 2 more answers

What is the value of this expression when a = 2 and b = -3 ? a^3 - b^3 / 5

saveliy_v [14]

Answer:

13 2/5

Step-by-step explanation:

a = 2 and b = -3

so the question asks whats.... a^3 - b^3/5

First we plug in the values of a and b

(2)^3 - (-3)^3 /5

Now we solve the ones in paranthesis first

(2)^3 = 8 because 2×2×2 and

-(-3)^3 forget about the - outside the parenthesis so

(-3)^3 = (-27) because (-3)×(-3)×(-3)

now we put it back together

8 -(-27)/5

the two minus become plus so

8 + 27/5

Now we solve it like fractions

8 and 27/5

simplify

13 and 2/5

Hope that helps!

5 0

3 years ago