Given that in the production of a plant, a treatment is being evaluated to germinate seed. From a total of 60 seed it was observed that 37 of them germinated

Let us check whether more than 50% will germinate using hypothesis test

$H_0: p = 0.50\\H_a: p>0.50\\$

(right tailed test)

Sample proportion p = $\frac{37}{60} =0.617\\q = 0.383\\Std error = \sqrt{\frac{pq}{n} } =0.0628$

p difference = 0.117

Test statistic Z = p difference/std error = 1.864

p value =0.0312

Since p value <0.05 our significance level of 5% we reject null hypothesis

It is possible to claim that most of the seed will germinate (i.e. more than 50%)

7 0

3 years ago

If someone could plz help. p÷5=3.

klio [65]

Answer:

p=2

Step-by-step explanation:

so how to find this u take the five and three and u subtract them both and whatever is left over that is your answer

4 0

3 years ago

Mrs. Rhodes is building the ramp shown below and she wants to paint it blue. How much paint will she need to cover the entire su

Mademuasel [1]

Answer:

2/3 of paint I believe because of the amount shown

4 0

3 years ago

Consider the function k(x)=x/5-3. Find k(-20).

marusya05 [52]

Answer:

-7

Step-by-step explanation:

k(x) = x/5 - 3

k(-20) = -20/5 -3

k(-20) = -4 - 3

k(-20) = -7

4 0

2 years ago