4 sq.units
area of a rectangle = length × breadth
length = 4units
breadth = 1units
A = l × b
= 4 × 1
= 4 sq.units
<h3>
<em>HOPE</em><em> </em><em>IT</em><em> </em><em>HELPS</em><em> </em><em>U</em><em> </em></h3>
<em>IF</em><em> </em><em>YES</em><em> </em>
<em>MARK</em><em> </em><em>ME</em><em> </em><em>AS</em><em> </em><em>THE</em><em> </em><em>BRAINLIEST</em>
Answer:
whats the question
Step-by-step explanation:
Outcome
Hope this helps :)
Answer:
A circle of radius = 7 or diameter = 14 or circumference = 43.98 meters has an area of: 0.0001539 square kilometers (km²) 153.9 square meters (m²) 1.539 × 10 6 square centimeters (cm²)
Step-by-step explanation:
can I get branliest please?
Answer:
m∠FEH = 44°
m∠EHG = 64°
Step-by-step explanation:
1) The given information are;
The angle of arc m∠FEH = 272°, the measured angle of ∠EFG = 116°
Given that m∠FEH = 272°, therefore, arc ∠HGF = 360 - 272 = 88°
Therefore, angle subtended by arc ∠HGF at the center = 88°
The angle subtended by arc ∠HGF at the circumference = m∠FEH
∴ m∠FEH = 88°/2 = 44° (Angle subtended at the center = 2×angle subtended at the circumference)
m∠FEH = 44°
2) Similarly, m∠HGF is subtended by arc m FEH, therefore, m∠HGF = (arc m FEH)/2 = 272°/2 = 136°
The sum of angles in a quadrilateral = 360°
Therefore;
m∠FEH + m∠HGF + m∠EFG + m∠EHG = 360° (The sum of angles in a quadrilateral EFGH)
m∠EHG = 360° - (m∠FEH + m∠HGF + m∠EFG) = 360 - (44 + 136 + 116) = 64°
m∠EHG = 64°.
