Answer:
Point A
Step-by-step explanation:
The long that would be used to find f(3) is the point that shows the value of y when x = 3.
Looking at the graph given, the only point that shows the value of y when x = 3 is point A.
When x = 3, y = 0.
Therefore, f(3) = 0.
You know, it would really be helpful if we could have a peek at
the picture that's "shown below". Just a peek would be enough.
Right now, the only thing I see below is my dog.
Now ... follow me here ... if you're looking for tan(r), then 'r' is
one of the angles in the triangle, and I'm guessing that all three
of those letters are angles.
tan(r) is going to be the ratio of two of the sides ... I mean
(one side) divided by (another side).
There's no way to go any farther, because you haven't given us
any names for the sides, or any way to describe them.
Betcha the names of the sides are on that picture that's supposed
to be shown below.
125 divides into both 625 and 1000. Divide each by 125 to get 5/8.
The perimeter of RSTU can be calculated alone without the help of MNPQ. It would be just 2(4) + 2(3) = 14 units. However, it would be much sensible if you want to find the parameter of the bigger rectangle. Since they are similar, you could use ratio and proportion.
(length/width)∨MNPQ = (length/width)∨RSTU
(x/9) = (3/4)
x = 6.75 units
Thus the perimeter of MNPQ is 2(6.75) + 2(9) = 31.5 units
Answer:
The solution to the system is
,
and
Step-by-step explanation:
Cramer's rule defines the solution of a system of equations in the following way:
,
and
where
,
and
are the determinants formed by replacing the x,y and z-column values with the answer-column values respectively.
is the determinant of the system. Let's see how this rule applies to this system.
The system can be written in matrix form like:
![\left[\begin{array}{ccc}5&-3&1\\0&2&-3\\7&10&0\end{array}\right]\times \left[\begin{array}{c}x&y&z\end{array}\right] = \left[\begin{array}{c}6&11&-13\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D5%26-3%261%5C%5C0%262%26-3%5C%5C7%2610%260%5Cend%7Barray%7D%5Cright%5D%5Ctimes%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7Dx%26y%26z%5Cend%7Barray%7D%5Cright%5D%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7D6%2611%26-13%5Cend%7Barray%7D%5Cright%5D)
Then each of the previous determinants are given by:
Notice how the x-column has been substituted with the answer-column one.
Notice how the y-column has been substituted with the answer-column one.

Then, substituting the values:


