<span> I am assuming you want to prove:
csc(x)/[1 - cos(x)] = [1 + cos(x)]/sin^3(x).
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<span>If we multiply the LHS by [1 + cos(x)]/[1 + cos(x)], we get:
LHS = csc(x)/[1 - cos(x)]
= {csc(x)[1 + cos(x)]/{[1 + cos(x)][1 - cos(x)]}
= {csc(x)[1 + cos(x)]}/[1 - cos^2(x)], via difference of squares
= {csc(x)[1 + cos(x)]}/sin^2(x), since sin^2(x) = 1 - cos^2(x).
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<span>Then, since csc(x) = 1/sin(x):
LHS = {csc(x)[1 + cos(x)]}/sin^2(x)
= {[1 + cos(x)]/sin(x)}/sin^2(x)
= [1 + cos(x)]/sin^3(x)
= RHS.
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<span>I hope this helps! </span>
I think the mode is 9.875
Answer:
well if this is by 300meters in one minutes then it would be 2400 meters
Rearrange to
6ab+21b-8a-28 now factor 1st and 2nd pair of terms...
3b(2a+7)-4(2a+7)
(3b-4)(2a+7)
So it is the third one down...
Converges by p series test
top section is almost constant, can never be larger than 3
so, compare degrees of their exponents, in this case it’s at a maximum of 3/1000n^2. the same as saying (3/1000)*summation of p series.
converges absolutely.