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Studentka2010 [4]
3 years ago
5

What is the mode and range of 12,11,14,16,14,12,16,14

Mathematics
2 answers:
Nina [5.8K]3 years ago
6 0
I think the mode is 9.875
Anastaziya [24]3 years ago
5 0
Range is the difference between the highest and lowest number
mode is the most common or repeated number

14 is mode since it is repeated 3 times

range is 16-11=5
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The area of a rectangle is represented by (x^2-14x-32) square units . If the width of the rectangle is represented by (x+2) unit
Flura [38]

The expression for length of rectangle is (x - 16) units

<h3><u>Solution:</u></h3>

Given that area of a rectangle is represented by x^2-14x-32 square units

width of the rectangle is represented by (x+2) units

To find: length of the rectangle

<em><u>The area of rectangle is given as:</u></em>

\text { area of rectangle }=\text { length } \times \text { width }

Substituting the values in formula, we get

x^{2}-14x-32=\text{length} \times(x+2)  ---- eqn 1

Let us first factorise the L.H.S of eqn 1

x^{2}-14x-32

Break the expression into groups

=\left(x^2+2x\right)+\left(-16x-32\right)

\mathrm{Factor\:out\:}x\mathrm{\:from\:}x^2+2x\mathrm{:\quad }x\left(x+2\right)

\mathrm{Factor\:out\:}-16\mathrm{\:from\:}-16x-32\mathrm{:\quad }-16\left(x+2\right)

=x\left(x+2\right)-16\left(x+2\right)

\mathrm{Factor\:out\:common\:term\:}x+2

=\left(x+2\right)\left(x-16\right)

Now substitute the above value in eqn 1

(x + 2)(x - 16) = length \times (x + 2)

length = \frac{(x + 2)(x - 16)}{x + 2}

Length = x - 16

Thus the expression for length of rectangle is (x - 16) units

8 0
3 years ago
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