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3 years ago

गुणोत्तर अनुक्रम र श्रेणी (GEOMETIC SEQUENCE & SERIES)

Mathematics

1 answer:

Anuta_ua [19.1K]3 years ago

7 0

Answer:

i think its 34

Step-by-step explanation:

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Se lanza un objeto desde una plataforma.

jasenka [17]

Answer:

6 seconds

Step-by-step explanation:

The question in English is

An object is thrown from a platform.

Its height (in meters), x seconds after launch, is modeled by:

h(x)=-5x^2+20x+60

How many seconds after the launch does the object reach the ground?

Let

x ----> the time in seconds

h(x) ---> the height of the object

we have

$h(x)=-5x^2+20x+60$

we know that

When the object hit the ground the height is equal to zero

For h(x)=0

we have

$-5x^2+20x+60=60$

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$-5x^2+20x+60=60$

$a=-5\\b=20\\c=60$

substitute in the formula

$x=\frac{-20\pm\sqrt{20^{2}-4(-5)(60)}} {2(-5)}$

$x=\frac{-20\pm\sqrt{1,600}} {-10}$

$x=\frac{-20\pm40} {-10}$

$x=\frac{-20+40} {-10}=-2$

$x=\frac{-20-40} {-10}=6$

The solution is x=6 sec

The he object reach the ground at x=6 seconds

7 0

3 years ago

Which of the following is a correct cosine ratio for the figure?

Elena L [17]

Answer:

Step-by-step explanation:

Cosine is adjacent / hypotenuse, so 12/13

7 0

2 years ago

0.00777x4.5/270,000 write in scientific notation

iris [78.8K]

Answer:

$87 {6 \frac{?}{?} ?}^{2}$

multi

4 0

3 years ago

20 copies of the school yearbook together weigh 50 lb what is the weight of each book

dedylja [7]

Answer:

2.5 pounds per book

Step-by-step explanation:

Set up a proportion

20 copies / 50 pounds = 1 copy / x pounds

Cross multiply

20x = 50

Divide both sides by 20

x = 2.5 pounds

I hope this helped and please mark me as brainliest!

6 0

2 years ago

In this 2x3 grid, each lattice point is one unit away from its nearest neighbors. A total of 14 isosceles triangles(but not righ

pickupchik [31]

The area of a shape is the amount of space it can occupy.

The number of isosceles triangle in the grid is: $\mathbf{\frac{2x^2}{u^2}}$

The dimension of the grid is given as:

$\mathbf{Dimension = x\ by\ x}$

Calculate the area

$\mathbf{A_1 = x\ \times \ x}$

$\mathbf{A_1 = x^2}$

The area of each isosceles triangle is given as:

$\mathbf{A_2 = \frac 12u^2}$

The number (n) of the triangle in an x-by-x grid is:

$\mathbf{n = A_1 \div A_2}$

So, we have:

$\mathbf{n = x^2 \div \frac 12u^2}$

Express as products

$\mathbf{n = x^2 \times \frac{2}{u^2}}$

$\mathbf{n = \frac{2x^2}{u^2}}$

Hence, the number of isosceles triangle in the grid is: $\mathbf{\frac{2x^2}{u^2}}$