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photoshop1234 [79]
3 years ago
6

The eleventh term from the end of the AP 14, 19, 24, …………., 264 is

Mathematics
1 answer:
vazorg [7]3 years ago
6 0

Answer:

<h2>The eleventh term of the sequence is 64</h2>

Step-by-step explanation:

The sequence given is an arithmetic sequence

14, 19, 24, …………., 264

The nth term of an arithmetic sequence is given as;

Tn = a+(n-1)d where;

a is the first term = 14

d is the common difference = 19-14=24-19 = 5

n is the number of terms = 11(since we are to look for the eleventh term of the sequence)

substituting the given values in the formula given;

T11 = 14+(11-1)*5

T11 = 14+10(5)

T11 = 14+50

T11 = 64

The eleventh term of the sequence is 64

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PLs help asap :( i have no idea how to do sigma notation
svet-max [94.6K]

The correct answer is C

Sigma Notation is when we take all of the whole numbers between the starting point (which can be found as the number under the sigma sign) and the end number (which can be found above the sigma sign). Therefore, we will add together all of the values of 3k + 2 for when k is equal to all of the numbers between 2 and 7. So, let's evaluate each one first.

When k = 2

3(2) + 2 = 8

When k = 3

3(3) + 2 = 11

When k = 4

3(4) + 2 = 14

When k = 5

3(5) + 2 = 17

When k = 6

3(6) + 2 = 20

When k = 7

3(7) + 2 = 23

So we know we have the following.

8 + 11 + 14 + 17 + 20 + 23

Now for the number after the comma, we are just looking for the answer of them all added together. So the final answer should be

8 + 11 + 14 + 17 + 20 + 23, 93


6 0
3 years ago
The answer to this problem?
LenaWriter [7]

The simplified expression of \sqrt{\frac{162x^9}{2x^{27}}} is \frac{9}{x^9}

<h3>How to simplify the expression?</h3>

The expression is given as:

\sqrt{\frac{162x^9}{2x^{27}}}

Divide 162 and 2 by 2

\sqrt{\frac{81x^9}{x^{27}}}

Take the square root of 81

9\sqrt{\frac{x^9}{x^{27}}}

Apply the quotient rule of indices

9\sqrt{\frac{1}{x^{27-9}}}

Evaluate the difference

9\sqrt{\frac{1}{x^{18}}}

Take the square root of x^18

\frac{9}{x^9}

Hence, the simplified expression of \sqrt{\frac{162x^9}{2x^{27}}} is \frac{9}{x^9}

Read more about expressions at:

brainly.com/question/723406

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Answer:

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● Within the SAT group, which is at the same time a group of neighbors who share possibilities and problems, learning to dialogue is both an educational objective and a means of training.

Step-by-step explanation:

The purpose of the SAT is for graduates to be competent to perform in their own communities at different levels of activity. The Booster, for example, works at the level of improvement of productive projects within its own productive units or those of its neighbors. The Pilot, in addition to the previous capacity, can organize different types of activities for the common good (health projects, the environment, work with children, recreation, production in solidarity). These two levels are approved by law with the basic secondary. At the Bachelor level, graduates are trained to participate in more complex organizations and develop long-term initiatives in both productive and organizational aspects.

To achieve greater ease and adaptation to the SAT, <em><u>I consider that the group that is being taught with the non-traditional method and where the students work in groups, can easily adapt to the SAT learning system.</u></em>

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3 years ago
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Answer:

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