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photoshop1234 [79]
4 years ago
6

The eleventh term from the end of the AP 14, 19, 24, …………., 264 is

Mathematics
1 answer:
vazorg [7]4 years ago
6 0

Answer:

<h2>The eleventh term of the sequence is 64</h2>

Step-by-step explanation:

The sequence given is an arithmetic sequence

14, 19, 24, …………., 264

The nth term of an arithmetic sequence is given as;

Tn = a+(n-1)d where;

a is the first term = 14

d is the common difference = 19-14=24-19 = 5

n is the number of terms = 11(since we are to look for the eleventh term of the sequence)

substituting the given values in the formula given;

T11 = 14+(11-1)*5

T11 = 14+10(5)

T11 = 14+50

T11 = 64

The eleventh term of the sequence is 64

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Step-by-step explanation:

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alexandr1967 [171]

The solution to the given equation is x = ±7. The correct option is d. x = ±7

<h3>Solving quadratic equations </h3>

From the question, we are to determine the solution to the given equation

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