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Harman [31]
3 years ago
14

Can an empty set be a universal set?

Mathematics
2 answers:
sertanlavr [38]3 years ago
8 0

Answer:

The empty set is defined as the complement of the universal set. That means where Universal set consists of a set of all elements.

elixir [45]3 years ago
6 0

Answer:

The empty set is defined as the complement of the universal set. That means where Universal set consists of a set of all elements, the empty set contains no elements of the subsets. The empty set is also called a Null set and is denoted by '{}'.

HOPE IT HELP YOU!

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Write an expression that is equivalent to 4n – 12 + 8y + (-3n).
Dimas [21]
It would be 1n - 12 + 8y.
4n - 3n = 1n
12 + 8y don’t mix so we can leave it.
Therefore: 1n - 12 + 8y
7 0
3 years ago
. If her allowance had stayed the same, $9.00 a month, how many carnival tickets could she bu
jarptica [38.1K]

Answer:

a) number of tickets she could buy in a month with her allowance in 2008 = 4 tickets

b) number of tickets she could buy in a month with the same allowance in 2012 = 2 tickets

c) $5, an increase of 55.56%

d) $2, a 100% increase.

e) Hallie was able to buy more tickets in 2008 than in 2012.

f) $16

Step-by-step explanation:

The complete question is presented in the attached image to this answer.

a) Halie's allowance monthly = $9

Price of a ticket in 2008 = $2

number of tickets she could buy in a month with her allowance = (9/2) = 4.5 = 4 tickets (since there are no half tickets)

b) Halie's allowance monthly = $9

Price of a ticket in 2012 = $4

number of tickets she could buy in a month with her allowance = (9/4) = 2.25 = 2 tickets (since there are no quarter tickets)

c) In 2012, Hallie's allowance was $14.00 per month. How much did her monthly allowance increase between 2008 and 2012?

Her monthly allowance in 2008 = $9

Her monthly allowance in 2012 = $14

The increase = new allowance - old allowance = 14 - 9 = $5

In percentage terms,

% increase = 100% × (new - old)/(old)

% increase = 100% × (14 - 9)/9 = 55.56%

d) How much more did a carnival ticket cost in 2012 than it did in 2008?

Price of a ticket on 2008 = $2

Price of a ticket in 2012 = $4

Increase in price = 4 - 2 = $2

% increase = 100% × (4 - 2)/2 = 100%

e) Was Hallie able to buy more carnival tickets in 2008 or in 2012 with one month's allowance?

Hallie was able to buy more tickets in 2008 than in 2012.

f) What would Hallie's allowance need to be in 2012 in order for her to be able to buy as many carnival tickets as she could in 2008?

Hallie could buy 4 tickets in 2008.

Price of a ticket in 2012 = $4.

Price of 4 tickets in 2012 = 4 × $4 = $16

Hope this Helps!!!!

3 0
2 years ago
Help me quick please --4x-7-3x+4=25
V125BC [204]

Answer:

<h2><em><u>x</u></em><em><u> </u></em><em><u>=</u></em><em><u> </u></em><em><u>32</u></em></h2>

Step-by-step explanation:

4x - 7 - 3x + 4 =25

=> 4x - 3x = 25 + 7

=> <em><u>x = 32 (Ans)</u></em>

3 0
3 years ago
Read 2 more answers
Suppose a flare is shot from the top of a 120 foot building at a speed of 160 feet per second. The equation h = ?16t + 160t + 12
insens350 [35]

Answer:

The time taken for the flare to hit the ground is approximately 10.7 seconds.

Step-by-step explanation:

Given : Suppose a flare is shot from the top of a 120 foot building at a speed of 160 feet per second. The equation h =- 16t^2+ 160t + 120 models the h height at t seconds of the flare.

To find : How long will it take for the flare to hit the ground?

Solution :

The equation  h =- 16t^2+ 160t + 120 models the h height at t seconds of the flare.

The flare to hit the ground when h=0.

Substitute in the equation,

-16t^2+ 160t + 120=0

Applying quadratic formula, x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

Where, a=-16, b=160 and c=120

x=\frac{-160\pm\sqrt{160^2-4(-16)(120)}}{2(-16)}

x=\frac{-160\pm\sqrt{33280}}{-32}

x=\frac{-160\pm 182.42}{-32}

x=\frac{-160+182.42}{-32},\frac{-160-182.42}{-32}

x=−0.70,10.70

Reject the negative value.

Therefore, the time taken for the flare to hit the ground is approximately 10.7 seconds.

4 0
3 years ago
ASAP PLZ HELP!!
Dominik [7]

Answer:

A) y² - 5y + 1

B) y² - 5y - 4

C) - 5y + 1

D) - 3y² - 4y - 6

Step-by-step explanation:

Let's call P the unkown polynomial and D the difference. In each case, the following must be true:

y² - 5y + 1 - P = D

<em>A)</em>

y² - 5y + 1 - P = 0

y² - 5y + 1 = P

<em>B)</em>

y² - 5y + 1 - P = 5

y² - 5y + 1 - 5 = P

y² - 5y - 4 = P

<em>C)</em>

y² - 5y + 1 - P = y²

y² - 5y + 1 - y² = P

- 5y + 1 = P

<em>D) </em>

y² - 5y + 1 - P = 4y² - y + 7

y² - 5y + 1 - 4y² + y - 7 = P

- 3y² - 4y - 6 = P

4 0
3 years ago
Read 2 more answers
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