Answer:
25kJ
Explanation:
K = 1/2 mv^2 = 1/2 x 2000kg x (5.0m/s)^2
= 25 x 10^3 J = 25kJ
The charges are the same in absolute value, so the change of potential energy is the same. That means that the change in kinetic energy is also the same. Then:
1 = Ke/Kp = m_e *v_e^2 / m_p * v_p^2, or
v_e/v_p = sqrt( m_p/m_e),
So the speed of the electron will be sqrt( m_p/m_e) times greater than the speed of the proton
To solve this problem it is necessary to apply the concepts related to the conservation of energy, specifically the potential elastic energy against the kinetic energy of the body.
By definition this could be described as


Where
k = Spring constant
x = Displacement
m = mass
v = Velocity
This point is basically telling us that all the energy in charge of compressing the spring is transformed into the energy that allows the 'impulse' seen in terms of body speed.
If we rearrange the equation to find v we have

Our values are given as



Replacing at our equation we have then,



Therefore he speed of the car before impact, assuming no energy is lost in the collision with the wall is 2.37m/s
Answer:
<h2>9.3kN</h2>
Explanation:
Step one:
given data
mass of bullet= 0.02kg
speed v=700m/s
time taken =1.5ms= 0.0015 seconds
Step two:
we know that from the first law
F=ma-----1 first law of motion
also, we know that
a=v/t----2
put a=v/t in equation 1 we have
F=mv/t
Step three:
substitute our given data to find force
F=0.02*700/0.0015
F=14/0.0015
F=9333.33N
F=9.3kN
<u>The average force exerted is 9.3kN</u>
Answer:
3,200 grams
Explanation:
recall that a hectogram = 100 grams
therefore
32 hectograms = 32 x 100 = 3,200 grams