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Alex787 [66]
3 years ago
5

. The p.d. at the terminals of a battery is 25V when no load is connected and 24V when a load taking 10A is connected. Determine

the internal resistance of the battery.
Physics
1 answer:
makvit [3.9K]3 years ago
6 0

Answer:

the internal resistance of the cell is 0.1 ohm.

Explanation:

Given;

p.d at the terminals of a battery at no load, E₁ = 25 V

p.d at the terminals of a battery at a load, E₂ = 24 V

current through the circuit, I = 10 A

The potential drop across the circuit, V = E₁ - E₂

                                                              = 25 V -  24 V

                                                               = 1 V

The internal resistance of the cell is calculated as follows;

r = V/I

r = 1 / 10

r = 0.1 ohm

Therefore, the internal resistance of the cell is 0.1 ohm.

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A comet is first seen at a distance of d astronomical units from the Sun and it is traveling with a speed of q times the Earth’s
saw5 [17]

To solve this problem it is necessary to take into account the concepts of Gravitational Force and Kinetic Energy.

The kinetic energy is given by the equation:

F= \frac{mv^2}2

La energía gravitacional por,

F=\frac{GM_cm}{d}

Where m is the mass, v is the velocity, G the gravitational constant M_e the mass of the earth, m the mass of the sun and d the distance ..

The sum of the energies, we must be a total energy

E= \frac{mv^2}2+\frac{GM_em}{d}

By the type of orbit we know that

E> 0 is a hyperbolic orbit

E = 0 is a parabolic orbit

E <0 is a closed orbit.

In the case of hyperbolic orbit

E>0

\frac{mq^2}{2}-\frac{GM_em}{d}>0\\\frac{qv^2_e}{2}>\frac{GM_em}{d}\\q^2d>2\frac{GM_e}{v^2_e}\\q^2d>2

The case of the comet is a closed orbit, so,

E<0

\frac{mv^2}2+\frac{GM_em}{d}

For parabolic orbit

E=0

\frac{mv^2_eq^2}{2}-\frac{GM_cm}{d}=0\\\frac{v^2_eq^2}{2}=\frac{GM_c}{d}\\q^2d=2\frac{GM_e}{v^2_e}\\q^2d=2

For the sun and the earth

\frac{m_ev_e^2}{r}=\frac{GM_em_e}{r^2}

v^2_e=\frac{GM_e}{r}\\\frac{GM_e}{v_e}=r

where R \approx 1AU

q^2d  For elliptical orbit

8 0
3 years ago
A spherical balloon is being inflated and the radius of theballoon is increasing at a rate of 2 cm/s.(A) Express the radius (r)
goblinko [34]

Answer:

A.) r = 2t

B.) V = 33.5t^3

Explanation:

Given that a spherical balloon is being inflated and the radius of the balloon is increasing at a rate of 2 cm/s

A) Express the radius (r) of the balloon as a function of the time (t).

Since the rate = 2 cm/s that is,

Rate = radius/ time

Therefore,

2 = r/t

Make r the subject of formula

r = 2t

(B) If V is the volume of the balloon as a function of the radius, find V or and interpret it.

Let assume that the balloon is spherical. Volume of a sphere is;

V = 4/3πr^3

Substitute r = 2t into the formula

V = 4/3π(2t)^3

V = 4/3π × 8t^3

V = 32/3 × πt^3

V = 33.5t^3

6 0
3 years ago
Learning Goal: To be able to calculate work done by a constant force directed at different angles relative to displacement
svlad2 [7]

Answer:

Woke done, W = 4156.92 Joules

Explanation:

The work done by the force can be calculated as :

W=F\times s

W=Fs\ cos\theta

\theta is the angle between force and the displacement

It is assumed to find the work done for the given parameters i.e.

Force, F = 30 N

Distance travelled, s = 160 m

Angle between force and displacement, \theta=30

Work done is given by :

W=Fs\ cos\theta

W=30\times 160\ cos(30)

W = 4156.92 Joules

So, the work done by the object is 4156.92 Joules. Hence, this is the required solution.

5 0
3 years ago
Why was Earth very hot at the beginning of its formation? Select all that apply.
Sladkaya [172]

Answer:

heat came from the supernova that led to the formation of solar system

4 0
3 years ago
A woman is standing in the ocean, and she notices that after a wave crest passes, five more crests pass in a time of 54.0 s. The
timama [110]

Answer:

a) f=0.1 Hz ; b) T=10s

c)λ= 36m

d)v=3.6m/s

e)amplitude, cannot be determined

Explanation:

Complete question is:

Determine, if possible, the wave's (a) frequency, (b) period, (c) wavelength, (d) speed, and (e) amplitude.

Given:

number of wave crests 'n'= 5

pass in a time't' 54.0s

distance between two successive crests 'd'= 36m

a) Frequency of the waves 'f' can be determined by dividing number of wave crests with time, so we have

f=n/t

f= 5/ 54 => 0.1Hz

b)The time period of wave 'T' is the reciprocal of the frequency

therefore,

T=1/f

T=1/0.1

T=10 sec.

c)wavelength'λ' is the distance between two successive crests i.e 36m

Therefore, λ= 36m

d) speed of the wave 'v' can be determined by the product of frequency and wavelength

v= fλ => 0.1 x 36

v=3.6m/s

e) For amplitude, no data is given in this question. So, it cannot be determined.

5 0
3 years ago
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