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MariettaO [177]
2 years ago
14

Gabriel invested $900 in an account paying an interest rate of 3 1/4 % compounded daily. Daniel invested $900 in an account payi

ng an interest rate of 3 3/8 % compounded continuously. After 19 years, how much more money would Daniel have in his account than Gabriel, to the nearest dollar?
Mathematics
1 answer:
Helen [10]2 years ago
3 0

Answer:

$40

Step-by-step explanation:

The earnings of Gabriel can be calculated with the formula:

P = Po * (1 + r/n)^(nt)

Where P = 900, r = 0.0325, n = 365 and t = 19

So we have:

P = 900 * (1 + 0.0325/365)^(365*19) = $1,668.81

The earnings of Daniel can be calculated with the formula:

P = Po * e^(rt)

Where Po = 900, r = 0.03375 and t = 19

So we have:

P = 900 * e^(0.03375*19) = $1,708.97

So the amount that Daniel will have more than Gabriel is:

1708.97 - 1668.81 = $40.16

Rounding to nearest dollar, the difference is $40

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The change to the face 3 affects the value of P(Odd Number)

Step-by-step explanation:

Analysing the question one statement at a time.

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The sample space becomes:

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The probability of each is:

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