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enot [183]
4 years ago
7

How much would $200 invested at 4% interest compounded every 6 months be worth after 5 years?

Mathematics
1 answer:
Katena32 [7]4 years ago
5 0

200 x 4/100=8

5 x 2=10

8 x 10=80

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The probability of tossing heads with a standard coin is 1/2, because it is one of two possible outcomes. The probability of tos
spayn [35]

Answer:

  a) 1/64

  b) 1/4096

Step-by-step explanation:

As you can tell from the example, the exponent of 1/2 is the number of heads in a row.

a) p(6 heads in a row) = (1/2)^6 = 1/(2^6) = 1/64

b) p(12 heads in a row) = (1/2)^12 = 1/(2^12) = 1/4096

_____

<em>Additional comment</em>

The probability of a head is 1/2 because we generally are concerned with a "fair coin." That is defined as a coin in which each of the 2 possible outcomes has the same probability, 1/2. Similarly, a "fair number cube" has 6 faces, and the probability of each is defined to be the same as any other, 1/6. Loaded dice and unfair coins do sometimes show up in probability problems.

3 0
3 years ago
Which postulate or theorem proves that these two triangles are congruent?
mario62 [17]

Answer:

ASA postulate of congruency

Step-by-step explanation:

Here Given AE=ED and ∠BAE=∠CDE

Also if we clearly observe ∠AEB=∠CED

By ASA postulate those two triangles are congruent.

The ASA (Angle,Side,Angle) postulate states that if two triangles with two angles and the included angle are equal then the two triangles are congruent.

5 0
3 years ago
Read 2 more answers
Consider the probabilities of people taking pregnancy tests. Assume that the true probability of pregnancy for all people who ta
Valentin [98]

Using conditional probability, it is found that there is a 0.8462 = 84.62% probability that a woman who gets a positive test result is truly pregnant.

<h3>What is Conditional Probability?</h3>

Conditional probability is the probability of one event happening, considering a previous event. The formula is:

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

  • P(B|A) is the probability of event B happening, given that A happened.
  • P(A \cap B) is the probability of both A and B happening.
  • P(A) is the probability of A happening.

In this problem, the events are:

  • Event A: Positive test result.
  • Event B: Pregnant.

The probability of a positive test result is composed by:

  • 99% of 10%(truly pregnant).
  • 2% of 90%(not pregnant).

Hence:

P(A) = 0.99(0.1) + 0.02(0.9) = 0.117

The probability of both a positive test result and pregnancy is:

P(A \cap B) = 0.99(0.1)

Hence, the conditional probability is:

P(B|A) = \frac{0.99(0.1)}{0.117} = 0.8462

0.8462 = 84.62% probability that a woman who gets a positive test result is truly pregnant.

You can learn more about conditional probability at brainly.com/question/14398287

7 0
2 years ago
Simone paid $5.25 for 3 pounds of apples. Which equation represents the cost, in dollars, C, of buying a pounds of apples?
Shalnov [3]
I believe it is the first once because if a means the amount of apples and $1.75 is the amount paid for 1 apple, this answer would be correct.
5 0
3 years ago
Which expression is equivalent to StartFraction (3 m Superscript negative 1 Baseline n squared) Superscript negative 4 Baseline
koban [17]

Answer:

3m^{10}n^{-11}

Step-by-step explanation:

Given the expression \frac{(3m^{-1}n^{2})^{-4}   }{(2m^{-2}n)^{3}  }, we will use laws of indices to get the equivalent expression as shown below;

According to one of the law of indices,

\frac{a^{m} }{a^{n} } = a^{m-n}  \ and\ (a^{m})^{n} = a^{mn}

\frac{(3m^{-1}n^{2})^{-4}   }{(2m^{-2}n)^{3}  }\\= \frac{3m^{4}n^{-8}   }{2m^{-6}n^{3}  }\\= 3m^{(4-(-6))} * n^{-8-3}\\ = 3m^{10}n^{-11}

This gives the required expression

8 0
3 years ago
Read 2 more answers
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