If in the triangle ABC , BF is an angle bisector and ∠ABF=41° then angle m∠BCE=8°.
Given that m∠ABF=41° and BF is an angle bisector.
We are required to find the angle m∠BCE if BF is an angle bisector.
Angle bisector basically divides an angle into two parts.
If BF is an angle bisector then ∠ABF=∠FBC by assuming that the angle is divided into two parts.
In this way ∠ABC=2*∠ABF
∠ABC=2*41
=82°
In ΔECB we got that ∠CEB=90° and ∠ABC=82° and we have to find ∠BCE.
∠BCE+∠CEB+EBC=180 (Sum of all the angles in a triangle is 180°)
∠BCE+90+82=180
∠BCE=180-172
∠BCE=8°
Hence if BF is an angle bisector then angle m∠BCE=8°.
Learn more about angles at brainly.com/question/25716982
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Answer:
LJ and GE
Step-by-step explanation:
Answer:
the solution for x is x=40
If we want to has 100 in the denominator we have to divide numerator and denominator by 2. Then total value of fraction doesnt change.
Now read the fraction, its 23 hundreds, now just write as decimal, so,
0.23
Answer:
16. r(s)(t) =
r=2, s=3, t=4
(2)(3)(4)=
(2*3) = 6 ---> 6(4) = 24
final: 24
17. (r)(s)(t)(x)(y) =
r = 2, s = 3, t = 4, x = 5, y = 6
(2)(3)(4)(5)(6)
2*3=6
6*4=24
24*5= 120
120*6=720
final: 720
18. (7x + 2Y) =
x = 5, y = 6
rewrite---> = [7(5) + 2(6)]
[35 + 12] = 47
final: 47
hope this helpsss sorry took a while LOL
Step-by-step explanation:
q = 1; r = 2; s = 3; t = 4; x = 5; y = 6
