The equation of the plane that goes through these points is:
6x + 2y + z = 10.
<h3>How to find the equation of a plane given three points?</h3>
The equation of the plane is found replacing the points into the following equation:
ax + by + c = z.
For point A, we have that:
3b + c = 4.
For point B, we have that:
a + 2b + c = 0.
For point C, we have that:
-a + 6b + c = 4.
Hence the system is:
From the first equation, we have that:
c = 4 - 3b.
Replacing in the second, we have that:
a + 2b + 4 - 3b = 0
a - b = -4.
Replacing in the third, we have that:
-a + 6b + 4 - 3b = 4.
-a + 3b = 0.
a = 3b.
We have that a - b = -4, hence:
3b - b = -4
2b = -4
b = -2.
a = 3b, hence a = -6.
c = 4 - 3b -> c = 10.
Hence the equation is:
ax + by + c = z.
z = -6x - 2y + 10
6x + 2y + z = 10.
More can be learned about the equation of a plane at brainly.com/question/13854649
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Answer:
The answer is B. f(x) = (x − 1)(x − 2)(x + 1)(x + 2)
36 + 18 = 54
(1) 18/54 = 1/3 = 33%
43 + 24 = 67
(2) 24/67 = 36%
I hope these are right
Answer:
-¾
Step-by-step explanation:
gradient = delta y over delta x
gradient = 0 - 3 / 5 - 1
gradient = -3 / 4
There's an app called photomath that would be useful for these kinds of problems!
