Answer: EMI(Electromagnetic interference)
RFI(Radio frequency interference)
Explanation: Electromagnetic interference is the emission of the electromagnetic signal that can disturb the working of the other device.It invokes the disturbance that can create error, under-performance mechanism,distortion etc in the equipment.
Radio-frequency interference(RFI) is the radio-frequency signal that interferes the other device by creating noise and distortion. This leads to breaking of the operation and data error.
Other options are incorrect because cross talk is referred as undesired communication between signal ,attenuation is the degradation in the amplitude of any signal and extended length of cabling is increasing the length of the cable.Thus the correct answer is RFI and EMI.
The process or activity of writing computer programs.
Answer:
The answer is "Option C"
Explanation:
The property master is a genius proprietor, it will be directly to blame for the purchase, acquisition, development, correct setting and/or supervision of every support necessary to processing in a film, tv, and movies production, and certain option were wrong, which can be described follows:
- In option A, It is wrong, because it is a continuous short, that is taken in the same sets,
- In option B, It is a device, which is used in the motion picture.
- In option D, It is a wheel cart camera, that is used in the shooting, that's why it is wrong.
<span>B. organize thoughts and ideas, is your answer</span>
Answer:
public class Brainly
{
public static void main(String[] args)
{
BinaryConverter conv = new BinaryConverter();
String binStr = "01001101";
System.out.print(binStr + " in decimal is "+conv.BinToDec(binStr));
}
}
public class BinaryConverter
{
public int BinToDec(String binStr)
{
int d = 0;
while(binStr.length() > 0)
{
d = (d << 1) + ((binStr.charAt(0) == '1') ? 1: 0);
binStr = binStr.substring(1);
}
return d;
}
}
Explanation:
The program "eats" the string from left to right, and builds up the integer representation in variable "d" on the go. While there are digits left, it shifts the previous result to the left and sets the least signficant bit to 1 only if the corresponding string character is a 1.
