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SIZIF [17.4K]
4 years ago
9

How does the graph of the function f(x)=2x^3-1 differ from the graph of its parent function?

Mathematics
1 answer:
nataly862011 [7]4 years ago
7 0

Answer:

Graph of parent function stretch vertically by factor 2 and shifts 1 units down to get the graph of f(x).

Step-by-step explanation:

The given function is

f(x)=2x^3-1

Its parent function is  

g(x)=x^3

The translation is defined as

f(x)=kg(x+a)+b                ... (1)

Where, k is stretch factor, a is horizontal shift and b is vertical shift.

If 0<k<1, then the graph compressed vertically by factor k and if k>1, then the graph stretch vertically by factor k.

If a>0, then the graph shifts a units left and if a<0, then the graph shifts a units right.

If b>0, then the graph shifts b units up and if b<0, then the graph shifts b units down.

The given function can be written as  

f(x)=2g(x)-1         ...(2)

On comparing (1) and (2), we get

k=2,a=0,b=-1

It means graph of parent function stretch vertically by factor 2 and shifts 1 units down to get the graph of f(x).

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What is the length of the curve with parametric equations x = t - cos(t), y = 1 - sin(t) from t = 0 to t = π? (5 points)
zzz [600]

Answer:

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General Formulas and Concepts:

<u>Calculus</u>

Differentiation

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  • Derivative Notation

Basic Power Rule:

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  2. f’(x) = c·nxⁿ⁻¹

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Integration

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Arc Length Formula [Parametric]:                                                                         \displaystyle AL = \int\limits^b_a {\sqrt{[x'(t)]^2 + [y(t)]^2}} \, dx

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

\displaystyle \left \{ {{x = t - cos(t)} \atop {y = 1 - sin(t)}} \right.

Interval [0, π]

<u>Step 2: Find Arc Length</u>

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Topic: AP Calculus BC (Calculus I + II)

Unit: Parametric Integration

Book: College Calculus 10e

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